106 square feet.. your welcome
Answer:

Step-by-step explanation:
Hi!
Lets call:
T = temprature of the object
T₀ = temperature of surroundings
t = time
The rate of change of T is its derivative with respecto to time. If T > T₀, the object looses heat, so T decreases. Then, being k > 0:

In this case T₀ = 70ºF and k = 0.05/min. Then the differential equation is:

Answer:
x^2-6x+9
Step-by-step explanation:
(x-3)^2
(x-3)(x-3)
x^2-3x-3x+9
x^2-6x+9
Answer:
B
Step-by-step explanation:
Square both sides, and get s^2 = k3/p
next multiply both sides by p and get (s^2)(p)=k3
Therefore k3 equals s^2 times p