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3 years ago

Please help thank you!

Mathematics

1 answer:

Lena [83]3 years ago

6 0

1 is D, an angle bisector only cuts the original angle in half.

2 is
9x - 18 = 3x
6x - 18 = 0
6x = 18
x = 3

3 is 9(3) - 18 = 27 - 18 = 9

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I need help plz real onez plz

melamori03 [73]

The mean is 10.
To find the mean you add up all the numbers and divide by how many sets of numbers there were.
8+10+11+8+13=50
50/5=10.

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2 years ago

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SOMEONE HELP ME PLEASE

faust18 [17]

Answer:

The answer is either 1, 3, or 5

Step-by-step explanation:

There are 6 sides on a singular die and the die is rolled twice the first time it rolls onto 4 and the second onto an odd number. The only odd numbers on a 6 sided die are 1, 3, and 5.

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3 years ago

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The answers for number 5

VladimirAG [237]

The answer is c because of y=mx+b

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2 years ago

The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,

strojnjashka [21]

Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=400$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=80$ represent the population standard deviation

n=15 represent the sample size

2) Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$400-2.58\frac{80}{\sqrt{15}}=346.708$

$400+2.58\frac{80}{\sqrt{15}}=453.292$

So on this case the 99% confidence interval would be given by (346.708;453.292)

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that $t_{\alpha/2}=2.98$