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MaRussiya [10]
3 years ago
6

Find the equation of line passing through points A (1, 3) and B (3, 7).

Mathematics
1 answer:
Sidana [21]3 years ago
4 0

Solution:

To find the equation of line passing through points A (1, 3) and B (3, 7).

we know that, to derive the equation of a line we first need to calculate the slope of the line. Slope m of a line at points (x_{1} ,y_{1}) and (x_{2}, y_{2}) is given by - m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}.

Slope of the line at point A(1,3) and B(3,7)

m=\frac{7-3}{3-1}.

m=\frac{4}{2}.

m=2.

Equation of a line using a point and a slope , y-y_{1}= m(x-x_1)

y-3= 2(x-1)

y-3= 2x-2

y= 2x-2+3

y= 2x+1

The equation of line passing through points A (1, 3) and B (3, 7) : y= 2x+1

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Graph g is a translation of the graph of y= sin x (dashed line).a) write down the equation of g b) write down the coordinates of
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<em>a)  </em>G(x)= \sin x + 2<em />

<em>b) The coordinates of P are</em>

<em />\displaystyle \left( \frac{3\pi}{2},1\right)

Step-by-step explanation:

<u>Translation</u>

The dashed line shows the graph of the function

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a)

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