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attashe74 [19]
3 years ago
6

Suppose a star is undergoing a nuclear reaction. What happens to the elements around the star as it begins to emit more and more

electromagnetic radiation? The lighter elements are pushed farther away than the rocky materials. The rocky materials are broken down into smaller particles. The rocky materials are pulled in by the electromagnetic radiation. The lighter elements are burned up by the electromagnetic radiation.
Chemistry
2 answers:
AlladinOne [14]3 years ago
3 0
I think the correct answer would be the third option. As the elements around the star begins to emit more and more electromagnetic radiation, the rocky materials are pulled in by the electromagnetic radiation. They are being drawn closer to the star and there would be a very high chance of a nuclear fusion could happen. The pressure and the temperature in a star is so high that it could allow nuclear fusion to happen. As a matter of fact, most of the life of a start is made from hydrogen nuclei fusing together forming a helium nuclei. As it runs out of the hydrogen nuclei, it would fuse other nuclei forming other elements.<span />
mamaluj [8]3 years ago
3 0

Answer:

its C. The rocky materials are pulled in by the electromagnetic radiation.

Explanation:

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How many chloride ions are in 2.6 moles of CaCl2?
Rama09 [41]

Answer:

31.31× 10²³ number of Cl⁻ are present in 2.6 moles of CaCl₂ .

Explanation:

Given data:

Number of moles of CaCl₂ = 2.6 mol

Number of Cl₂ ions = ?

Solution:

CaCl₂  → Ca²⁺ + 2Cl⁻

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

In one mole of CaCl₂ there are two moles of chloride ions present.

In 2.6 mol:

2.6×2 = 5.2 moles

1 mole Cl⁻ =   6.022 × 10²³ number of Cl⁻ ions

5.2 mol ×  6.022 × 10²³ number of Cl⁻  / 1mol

31.31× 10²³ number of Cl⁻

8 0
3 years ago
You work for a cutlery manufacturer who wants to electrolytically precipitate 0.500 g of silver onto each piece of a batch of 25
ICE Princess25 [194]

Answer:

373.1 mL of AgCN (aq) must be poured into your electrolysis vat to ensure you have sufficient Ag to plate all of the forks.

Explanation:

Mass of silver to be precipitated on ecah spoon = 0.500 g

Number of silver spoons = 250

Total mass of silver = 250 × 0.500 g = 125 g

Moles (n)=Molarity(M)\times Volume (L)

Moles of AgCN = n  = \frac{125 g}{134 g/mol}=0.9328 mol

Volume of AgCN solution =V

Molarity of the AgCN = 2.50 M

V=\frac{0.9328 mol}{2.50 M}=0.3731 L=373.1 mL

(1 L = 1000 mL)

373.1 mL of AgCN (aq) must be poured into your electrolysis vat to ensure you have sufficient Ag to plate all of the forks.

6 0
3 years ago
Why this process is called a cycle
Greeley [361]
<span>because it is a pattern; airgo cycle</span>
5 0
3 years ago
Read 2 more answers
How much energy, in joules, does 150.0 g of water with an initial temperature of 25 C need to absorb be raised to a final temper
satela [25.4K]

Answer:

31395 J

Explanation:

Given data:

mass of water = 150 g

Initial temperature = 25 °C

Final temperature = 75 °C

Energy absorbed = ?

Solution:

Formula:

q = m . c . ΔT

we know that specific heat of water is 4.186 J/g.°C

ΔT = final temperature - initial temperature

ΔT = 75 °C - 25 °C

ΔT = 50 °C

now we will put the values in formula

q = m . c . ΔT

q = 150 g × 4.186 J/g.°C × 50 °C

q = 31395 J

so, 150 g of water need to absorb 31395 J of energy to raise the temperature from 25°C to 75 °C .

5 0
3 years ago
Standard reduction potentials for nickel(II) and copper(II) The standard reduction potential for a substance indicates how readi
AleksandrR [38]

Answer:

The standard potential, E cell, for this galvanic cell is 0.5670V

Explanation:

Ni²⁺(aq)  +  2e⁻   →   Ni(s)           E red =  - 0.23V      ANODE

Cu²⁺(aq) +  2e-    →  Cu(s)          E red = + 0.337V    CATHODE

ΔE° = E cathode - E anode

ΔE° = 0.337V - (0.23V) = 0.5670 V

6 0
3 years ago
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