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2 years ago

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Chemistry

1 answer:

Molodets [167]2 years ago

8 0

Answer:

A strip of magnesium metal is ignited using a lighter wand. The result is

an intensely glowing white light. As the burning of the metal subsides, a

white powder-like substance now appears replacing the smooth ribbon of

metal.

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Which balanced equation represents an oxidation-reduction reaction?

Bingel [31]

Answer:

Oxidation states are used in chemistry solutions. It is a bond in which electron transfers easily from one nucleus to another nucleus.

Explanation:

Oxidation-reduction reactions have some rules.
The oxidation state is 0 at an uncombined bond.
The bond of oxidation reduction is +1 in alkeli metal.
The bond in two metal is +2
The oxidation reduction state at helogens is -1. It does not happened always.
The oxygen bond in oxidation and reduction is -2.
The sum of the oxidation state is equal to the compound charges.
In this process the changes occur for any elements. Redox could be occur. Its oxidized and reduction reaction can be seen in this process.

7 0

2 years ago

A light source of wavelength, l, illuminates a metal and ejects photoelectrons with a maximum kinetic energy of 1 eV. A second l

madreJ [45]

Explanation:

From first source, kinetic energy ( $K.E_{1}$ ) ejected is 1 eV and wavelength of light is $\lambda$ .

From second source, kinetic energy ( $K.E_{2}$ ) ejected is 4 eV and wavelength of light is $\frac{\lambda}{2}$ .

Relation between work function, wavelength, and kinetic energy is as follows.

K.E = $\frac{hc}{\lambda} - \phi$

where, h = Plank's constant = $6.63 \times 10^{-34}$ J.s

c = speed of light = $3 \times 10^{8}$ m/s

Also, it is known that 1 eV = $1.6 \times 10^{-19}$ J

Therefore, substituting the values in the above formula as follows.

From first source,

$K.E_{1}$ = $\frac{hc}{\lambda} - \phi$

1 eV = $1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\lambda} - \phi$

$1.6 \times 10^{-19} J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (1)

From second source,

$K.E_{2}$ = $\frac{hc}{\lambda} - \phi$

$4 \times 1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\frac{\lambda}{2}} - \phi$

$6.4 \times 10^{-19} J = \frac{2 \times 1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (2)

Now, divide equation (2) by 2. Therefore, it will become

${6.4 \times 10^{-19}J}{2} = \frac{2 \times 1.98 \times 10^{-25} J.m}{2\lambda} - \frac{\phi}{2}$

$3.2 \times 10^{-19}J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \frac{\phi}{2}$ ......... (3)

Now, subtract equation (3) from equation (1), we get the following.

$1.6 \times 10^{-19} = \frac{\phi}{2}$

$\phi$ = $3.2 \times 10^{-19}$

= 2 eV

Thus, we can conclude that work function of the metal is 2 eV.

3 0

2 years ago

The human eye cannot see anything less than 40 micrometers in size. What is this length in meters?

Agata [3.3K]

Answer:

4e-5 is the length in meters

Have a nice day! :)

6 0

2 years ago

True or False: Just like protons, the

Nikolay [14]

Answer:

Please give brainlist if right I think it is True.

5 0

2 years ago

explain how solar radiation and convection currents on Earth. Describe how solar radiation and convection currents work together

Pepsi [2]

Answer:

Convection is the transfer of heat energy in a fluid. ... Air in the atmosphere acts as a fluid. The sun's radiation strikes the ground, thus warming the rocks.

Explanation:

3 0

2 years ago

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