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zheka24 [161]
4 years ago
11

What is the approximate percent increase when the population of a town increases from 12,089 to 15,025? Round the population amo

unts to the nearest thousand to find an estimate of the percent increase
Mathematics
1 answer:
Karo-lina-s [1.5K]4 years ago
3 0
\frac{2900}{12000} *100
=24.17 %
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H(a) = 3 - 2a find h(-3)
skelet666 [1.2K]

Answer:

h(-3)=9

Step-by-step explanation:

hope this helps

6 0
3 years ago
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Help with this question please and thanks in advance
SashulF [63]
Answer: x=39

3x-15=2x+24
-2x -2x
1x-15=24
+15 +15
x=39

Explanation: Non-consecutive angles are congruent. Set the two angles equal to each other and solve for x. You should get x=39.
3 0
3 years ago
Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=11x−3 and CE=12−4x. Find the length of AC.
Oxana [17]

Answer:

AC=16 units

Step-by-step explanation:

The diagonals of a parallelogram bisect each other.  It was given that diagonals AC and BD intersect at point E.

This implies that: AE=CE.

We substitute the expression for x, we get:

11x-3=12-4x.

Group similar terms to get:

11x+4x=12+3.

15x=15.

x=1

AC = 2(12-4x)

AC=2(12-4(1))

AC=2(8)

AC=16

8 0
3 years ago
Data consistent with summary quantities in the article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among
Olegator [25]

Answer:

a) X[bar]₁=  1839.20 cal

b) X[bar]₂= 1779.07 cal

c) S₁= 386.35 cal

Step-by-step explanation:

Hello!

You have two independent samples,

Sample 1: n₁= 15 children that did not eat fast food.

Sample 2: n₂= 15 children that ate fast food.

The study variables are:

X₁: Calorie consumption of a kid that does not eat fast food in one day.

X₂: Calorie consumprion of a kid that eats fast food in one day.

a)

The point estimate of the population mean is the sample mean

X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal

b)

X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal

c)

To calculate the sample standard deiation, you have to calculate the sample variance first:

S₁²= \frac{1}{n_1-1}[∑X₁² - (( ∑X₁)²/n₁)]= \frac{1}{14} + [52829538 - (\frac{27588^{2} }{15}) = 149263.4571 cal²

S₁= 386.35 cal

I hope it helps!

7 0
3 years ago
Perform the operation and write the answer in the simplest form....
Stels [109]
For dividing fractions you should always use the KCF method: Keep Change Flip
6/10 divided by 12/7 
Kcf method:
6/10*7/12= 42/120
42/120 in simplest form will be 7/20
So the answer is A

4 0
3 years ago
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