2 years ago

I NEED HELP WITH THIS ASAP

1 answer:

3 0

hopefully someone helps u with this tho sorry

You might be interested in

qwelly [4]

Maybe A I’m not one hundred percent sure but good luck

7 0

3 years ago

Lunna [17]

Answer:

The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

Step-by-step explanation:

Let x be the amount in the account at 12% interest

So, 6000-x is the amount in the second account at 7% interest

$SI = \frac{P \times T \times R}{100}$

First account: $SI=\frac{x \times 1 \times 12}{100}$

Second account : $SI =\frac{(6000-x) \times 1 \times 7}{100}$

We are given that At the end of the first year he had earned $590 in interest.

So, $\frac{x \times 1 \times 12}{100}+\frac{(6000-x) \times 1 \times 7}{100}=590\\x=3400$

So,the amount in the account at 12% interest is $3400

The amount in the second account at 7% interest =6000-x=6000-3400=2600

Hence the amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

8 0

3 years ago

julsineya [31]

The answer is 3:11 and 3 to 11

5 0

3 years ago

AnnyKZ [126]

56=2(pi)(r)
r=8.9127
pi(8.9127)^2=249.56cm^2
≈245cm^2 (3s.f.)

3 0

3 years ago

il63 [147K]

Answer: Which question?

Step-by-step explanation:

5 0

3 years ago