Answer:
The complete question is:
At a university, 13% of students smoke.
a) Calculate the expected number of smokers in a random sample of 100 students from this university:
b) The university gym opens at 9 am on Saturday mornings. One Saturday morning at 8:55 am there are 27 students outside the gym waiting for it to open. Should you use the same approach from part (a) to calculate the expected number of smokers among these 27 students?
Part a is easy, because is a random sample, we can expect that just 13% of these 100 students to be smokers, and 13% of 100 is 13, so we can expect 13 of those 100 students to be smokers.
b) This time we do not have a random sample, our sample is a sample of 15 students who go to the gym in the early morning, so our sample is biased. (And we do not know if this bias is related to smoking or not, and how that relationship is), so we can't use the same approach that we used in the previous part.
Answer:
Step-by-step explanation:
If a equation has two zeros x=a and x=b then equation can be written as
similarly if a equation has two zeros at x = −6 and x = 2
then equation can be written as
Therefore 
is required equation
A<span>. What proportion have SAT scores greater than 700? Z= 2 ; 2.28%
B. What proportion have SAT scores greater than 500? 50%
C. What is the minimum SAT score needed to be in the highest
10% of the population? Z= 1.28; 628
D. If the state college only accepts students from the top 60% of the SAT distribution, what is the minimum SAT score needed to be accepted? Z= .26; 474</span><span>
</span>
Answer:
The odds of getting a green M&M is 
and the probability of getting a green M&M is 
Step-by-step explanation:
Red candies = 14
Blue candies = 10
Green candies = 5
Brown candies = 11
Orange candies = 3
Yellow candies = 12
Total No. of candies = 14+10+5+11+3+12 = 55
(a) the odds of getting a green M&M
Green candies = 5
Total number of candies excluding green or unfavorable = 50
Odds of getting a green M&M = 
= 
=
(b) the probability of getting a green M&M
Green candies = 5
Total No. of candies = 55
So, the probability of getting a green M&M =
=
Hence the odds of getting a green M&M is and the probability of getting a green M&M is
Answer:
26
Step-by-step explanation:
26 times
