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qaws [65]
3 years ago
11

∠CAT and ∠TAD is a linear pair. If m∠CAT = 14 and m∠TAD = x+10, find x.(show work please)

Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0

Answer:

156

Step-by-step explanation:

Since, ∠CAT and ∠TAD is a linear pair.

Therefore,

∠CAT + ∠TAD = 180°

14° + (x + 10)° = 180°

(x + 24)° = 180°

x + 24 = 180

x = 180 - 24

x = 156

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Evaluate the following pic
GREYUIT [131]

Answer:

1) \sqrt{1225}+\sqrt{1024}=67

2)  \sqrt[3]{-1331}=-11

3) Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

Step-by-step explanation:

1) \sqrt{1225}+\sqrt{1024}

Prime factors of 1225 : 5x5x7x7

Prime factors of 1024: 2x2x2x2x2x2x2x2x2x2

\sqrt{1225}+\sqrt{1024}\\=\sqrt{5\times5\times7\times7}+\sqrt{2\times2\times2\times2\times2\times2\times2\times2\times2\times2}\\=\sqrt{5^2\times7^2}+\sqrt{2^2\times2^2\times2^2\times2^2\times2^2}\\=5\times7+(2\times2\times2\times2\times2)\\=35+32\\=67

\sqrt{1225}+\sqrt{1024}=67

2) \sqrt[3]{-1331}

We know that \sqrt[n]{-x}=-\sqrt[n]{x} \ ( \ if \ n \ is \ odd)

Applying radical rule:

\sqrt[3]{-1331}\\=-\sqrt[3]{1331} \\=-\sqrt[3]{11\times\11\times11}\\=-\sqrt[3]{11^3} \\Using \ \sqrt[n]{x^n}=x \\=-11

So, \sqrt[3]{-1331}=-11

3) 2:p :: p:8

It can be written as:

p*p=2*8\\p^2=16\\Taking \ square \ root \ on \ both \ sides\\\sqrt{p^2}=\sqrt{16}\\p=\pm 4

Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6

Put value of x, y and z in equation and solve:

x^3+y^2+z \\=(3)^3+(-2)^2+(-6)\\=27+4-6\\=25

So, x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}

We know (-a)^n = (a)^n when n is even and (-a)^n = (-a)^n when n is odd

\frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}\\\\=\frac{1296\times-8\times 27}{46656}\\\\=\frac{-279936}{46656} \\\\=-6

So, \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

8 0
2 years ago
Help me with this question please
sp2606 [1]
We add 548 and 225 which would be 773
7 0
3 years ago
#2) A lifeguard is swimming to a drowning swimmer. The lifeguard's location is at
Ulleksa [173]

Answer:

<h3>9.43</h3>

Step-by-step explanation:

The formula for calculating the distance between two points is expressed as

D =√(x2-x1)²+(y2-y1)²

Given the coordinates (0,0) and (8,5)

D = √(5-0)²+(8-0)²

D = √5²+8²

D = √25 + 64

D = √89

<em>D = 9.43</em>

<em>Hence the distance between the life guard and the swimmer is 9.43</em>

<em></em>

8 0
2 years ago
What is the factored form of the polynomial?
Ilya [14]
(x-9)(x-3), because -9 and -3 make a sum of -12 and a product of +27
4 0
2 years ago
Read 2 more answers
How can i solve (-4,7) , (-6,-4)
pishuonlain [190]

Answer:

(-6) - 7 and -6 - (-4)

Step-by-step explanation:

you have to find the rate of change.

this equals -13/4=3.25

5 0
3 years ago
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