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insens350 [35]
3 years ago
6

There are 11 paintings at an art show. Three of them are chosen randomly to display in the gallery window. The order in which th

ey are chosen does not matter. How many ways are there to choose the paintings?
Mathematics
2 answers:
Aneli [31]3 years ago
6 0

Answer:

165 ways  to choose the paintings

Step-by-step explanation:

This is clearly a Combination problem since we are selecting a few items from a group of items and the order in which we chosen the items does not matter.

The number of possible ways to choose the paintings is;

11C3 = C(11,3) = 165

C denotes the combination function. The above can be read as 11 choose 3 . The above can simply be evaluated using any modern calculator.

Phoenix [80]3 years ago
4 0

Answer:

165 ways

Step-by-step explanation:

Total number of painting, n = 11

Now, three of them are chosen randomly to display in the gallery window.

Hence, r = 3

Since, order doesn't matter, hence we apply the combination.

Therefore, number of ways in which 3 paintings are chosen from 11 paintings is given by

^{11}C_3

Formula for combination is ^nC_r=\frac{n!}{r!(n-r)!}

Using this formula, we have

^{11}C_3\\\\=\frac{11!}{3!8!}\\\\=\frac{8!\times9\times10\times11}{3!8!}\\\\=\frac{9\times10\times11}{6}\\\\=165

Therefore, total number of ways = 165

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Step-by-step explanation:

First, we should focus on their records and percents.

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When we subtract 35 and -15, we get the difference of 50.

We know 10% is 50 point difference, 20% is 100 point difference, 30% is 150 point difference, etc.

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