If x-1=0 and y+3=0, what is the value of x-y?

Mathematics

2 answers:

lozanna [386]3 years ago

7 0

Answer: $x - y = 4$

Step-by-step explanation:

$x - 1 = 0$

Add 1 to both sides of the equation , that is

$x - 1 + 1 = 0 + 1$

$x = 1$

Also

$y + 3 = 0$

subtract 3 from both sides of the equation , that is

$y + 3 - 3 = 0 - 3$

$y = -3$

Therefore :

$x - y = 1 - (-3)$

$x - y = 1 + 3$

$x - y = 4$

Vera_Pavlovna [14]3 years ago

5 0

Answer:

Step-by-step explanation:

x is 1

y is -3

1- - 3 is 1+3 which is 4

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I need help 6x-2y=10 x-2y=-5 solve by elimination

dem82 [27]

<h3><u>Explanation</u></h3>

Given the system of equations.

$\begin{cases} 6x - 2y = 10 \\ x - 2y = - 5 \end{cases}$

Solve the system of equations by eliminating either x-term or y-term. We will eliminate the y-term as it is faster to solve the equation.

To eliminate the y-term, we have to multiply the negative in either the first or second equation so we can get rid of the y-term. I will multiply negative in the second equation.

$\begin{cases} 6x - 2y = 10 \\ - x + 2y = 5 \end{cases}$

There as we can get rid of the y-term by adding both equations.

$(6x - x) + ( - 2y + 2y) = 10 + 5 \\ 5x + 0 = 15 \\ 5x = 15 \\ x = \frac{15}{5} \longrightarrow \frac{ \cancel{15}}{ \cancel{5}} = \frac{3}{1} \\ x = 3$

Hence, the value of x is 3. But we are not finished yet because we need to find the value of y as well. Therefore, we substitute the value of x in any given equations. I will substitute the value of x in the second equation.

$x - 2y = - 5 \\ 3 - 2y = - 5 \\ 3 + 5 = 2y \\ 8 = 2y \\ \frac{8}{2} = y \\ y = \frac{8}{2} \longrightarrow \frac{ \cancel{8}}{ \cancel{2}} = \frac{4}{1} \\ y = 4$