Ask question

Ask question

All categories

4 years ago

15

A California condor can have a mass of 13 kg. A B hummingbird can have a mass of 1.6 g. How many times is great as the bee hummi

ngbird mass is the California condors mass?

1 answer:

Vera_Pavlovna [14]4 years ago

6 0

The condor's mass is 8.125 times the hummingbird's mass.

You might be interested in

Let F be the function given by f(x)= 2xe^x. Determine the interval(s) on which the graph is concave down.

Vika [28.1K]

Hello,

y=2xe^x
y'=2(e^x+xe^x)=2(x+1)e^x
y''=2(e^x+(x+1)e^x)=2(x+2)e^x

x |-infinite -2 0 +infinite
e^x | ++++++++++++++++++
x+2 |------------0 +++++++++++
y'' | -----------0 +++++++++++

y''<0 if x<-2
<span>The interval on which the graph is concave down is (-infinite -2[</span>

7 0

3 years ago

In Scott’s backyard, he has a windmill that makes 5 ¾ of a turn every hour. How many turns does it make for 1 ½ hours?

DanielleElmas [232]

Answer: 8 5/8 turns

Step-by-step explanation:

Hi, to answer this question we have to simply to multiply the number of turns that the windmill makes per hour (5 3/4) by the time asked (1 ½ hours).

Mathematically speaking:

5 3/4 x 1 1/2 = (5x4+3)/4 x (1x2+1)/2 = 23/4 x 3/2= 69/8 or 8 5/8 (mixed form)

In conclusion, the windmill makes 8 5/8 turns in 1 1/2 hours.

3 0

4 years ago

Simplify 6/sqr3+2<br> NEED HELP PLZ!!

mote1985 [20]

Answer:

1.61

Step-by-step explanation:

6/((sqrt3)+2) in a calculator

5 0

3 years ago

Read 2 more answers

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

A rectangular block of metal measures 5 cm by 10 cm by 2 cm and has a mass of 700g. What is the density of the block of metal?

masha68 [24]

Volume = 5 cm * 10 cm * 2 cm
volume = 100 cm³
massa = 700 g
Densidade = massa / volume
D = 700/100
D = 7 g / cm³

5 0

3 years ago