Number of people can hold in each car = 10
Solution:
Number of cars in the Blazing Bullet = 6
Total number of people can ride at one time = 60
Number of people can hold at one Bullet car = ?
Let n be the number of people in each car can hold.
Now write a equation to find the number of people in each car.
Number of cars × number of people in each car = Total number of people
⇒ 6 × n = 60
⇒ 6n = 60
Now, solving this equation.
⇒ 6n = 60
Divide both sides of the equation by 6.
⇒ n = 10
Hence 10 people can hold in each car.
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Answer:
Answer choice C
Step-by-step explanation:
Similarly to the previous problem, there are two possibilities. In the first possibility, the chance of picking a digit lower than 7 is 6/9 or 2/3, because there are 6 digits below 7 and 9 digits in total. In this scenario, the probability of the second digit being below 7 is 5/8, since one of the digits has already been taken. The probability here is 5/8*6/9=5/12. In the other scenario, the probability of picking a number higher than 7 is 3/9 or 1/3. In this scenario, the probability of picking below 7 for the second digit is 6/8 or 3/4, because one of the digits has not been taken. 3/9*6/8= 1/4. Adding these two together, you get 8/12=2/3, or answer choice C. Hope this helps!
You are given h(t) = 64–16t^2.
You need to find h(1.25).
Set up:
h(1.25) = 64 - 16(1.25)^2
Take it from here.
