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SashulF [63]
3 years ago
6

Upon registration, new members of the American cD club receive 30 cDs for review. Each month the club sends its members 2 more c

Ds for their review. Bobby has purchased every CD sent to him. How many CDs has Bobby purchased during his 9 months of membership?
Mathematics
1 answer:
Pani-rosa [81]3 years ago
6 0
520 CD's because of the 9 months and we add 30 time 9 we erase the 0 and multiply the 3 with the 9 it will be 27 right we add the zero because the originla number is 30
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Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC =16 and DC=5 what is the length of BC in the simplest ra
Nana76 [90]

The length of BC is 4 \sqrt{5}.

Solution:

Given ABC is a right triangle.

AC is the hypotenuse and BD is the altitude.

AB and BC are legs of the triangle ABC.

AC = 16 and DC = 5

<u>Leg rule of geometric mean theorem:</u>

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

$\Rightarrow \frac{AC}{BC}=\frac{BC}{DC}$

$\Rightarrow \frac{16}{x}=\frac{x}{5}$

Do cross multiplication.

\Rightarrow  16\times 5 = x\times x

\Rightarrow  80= x^2

\Rightarrow  16\times 5= x^2

Taking square root on both sides.

\Rightarrow  \sqrt{16\times 5} = \sqrt{x^2}

\Rightarrow  \sqrt{4^2\times 5} = \sqrt{x^2}

square and square roots get canceled, we get

\Rightarrow  4\sqrt{ 5} = x

The length of BC is 4 \sqrt{5}.

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3 years ago
How many centimeters long is a 21 board
scoundrel [369]
21, it says it right in the name.
3 0
3 years ago
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I need help with solving it
mars1129 [50]

The given equation has a slope of \frac{-9}{7}.  Parallel lines have the same slope.

Point-Slope formula: y - y₁ = m(x - x₁)  ; where (x₁, y₁) is the point and "m" is slope

y - y₁ = m(x - x₁)

y - (-4) = \frac{-9}{7}(x - 2)

y + 4 = \frac{-9}{7}x + \frac{18}{7}

<u>  - 4</u>     <u>       - \frac{28}{7}</u>

   y = \frac{-9}{7}x - <u>\frac{10}{7}</u>


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3 years ago
I need.help please
Scrat [10]
It is 100 times greater


8 0
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The box plots show the weights, in pounds, of the dogs in two different animal shelters.
Dmitriy789 [7]

Answer:

The median weight for shelter A is greater than that for shelter B.

The data for shelter B are a symmetric data set.

The interquartile range of shelter A is greater than the interquartile range of shelter B.

Step-by-step explanation:

The median weight for shelter A is greater than that for shelter B.

The median of A = 21 and the median of B = 18  true

The median weight for shelter B is greater than that for shelter A.

The median of A = 21 and the median of B = 18   false

The data for shelter A are a symmetric data set.

False, looking at the box it is not symmetric

The data for shelter B are a symmetric data set.

true, looking at the box it is  symmetric

The interquartile range of shelter A is greater than the interquartile range of shelter B.

IQR = 28 - 17 = 11 for A

IQR for B = 20 -16 = 4  True

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