Answer:
(3,-3)
Explanation:
create an equation set equal to zero:
3×(1,-1)=0
distributive property:
3×1= 3 ; 3× -1= -3
(3,-3)=0
Since there are two events happening simultaneously (windy and no sun), we can apply the concept of conditional probability here.
P(A|B) = P(A∩B)/P(B)
where it means that given B is happening, the probability that A is happening as well is the ratio of the chance for A and B to happen simultaneously over the chance of B to happen.
For our case, this can be interpreted as
P(A|B): it is the probability that it is windy (A) GIVEN that there is no sun (B)
P(A∩B) : chance of wind and no sun
P(B) : chance that there is no sun tomorrow
The chance of P(A∩B) is already given as 20% or 0.20. Since there is 10% or 0.10 chance of sun, then chances of having no sun tomorrow is (1-0.10) = 0.90.
Thus, we have P(A|B) = 0.2/0.9 ≈ 0.22 or 22%.
So, answer is B: 22%<span>.</span>
3(2x)=4x+4
do the bracket first
(3)(2x)= 6x
6x= 4x+4
move 4x to the other side
sign changes from +4x to -4x
6x-4x=4x-4x+4
6x-4x= 4
2x= 4
divide by 2
2x/2=4/2
x=2
Answer: x= 2
I'm sorry but you're on your own for this one. This isn't difficult to do, or you can even make it up the numbers within reason
