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Salsk061 [2.6K]
1 year ago
14

SAT Math Question

Mathematics
1 answer:
mariarad [96]1 year ago
5 0

I'm tentatively changing my answer to say this kind of relies on practical knowledge of how stores tend to operate. If 20 coupons are given out, the store has sold all 500 shirts, arguably at a loss to the retailer. They have to have more shirts in stock to be sold at full price because, well, that's how they make money. It's more likely that such a store would carry more than just 500 shirts at the start of each day, so A is (probably) wrong.

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Ron earned $95 in interest for leaving $1,000 in an account for 3 years. What was his rate? Round to the nearest hundredth (2 de
taurus [48]

Answer:

x=0.0307

Step-by-step explanation:

6 0
2 years ago
Round 0.485 correct to 1 significant figure
yanalaym [24]

Answer:

0.5

Step-by-step explanation:

the first significant figure is the non zero

6 0
2 years ago
A city is 7,642 feet above sea level. Is this elevation closer to the highest point or the lowest point?
tekilochka [14]

Answer:

It must be closer to the lowest point.

Step-by-step explanation:

There is a simple and a general explanation to it. As it gets higher up from the sea level, the elevation gets closer to the lowest point simply because the distance from the highest point keeps decreasing as you get closer. The elevation is the distance left between the highest point and the current point.

3 0
3 years ago
Evaluate the integral by making an appropriate change of variables.
VARVARA [1.3K]

By inspecting the integrand, the "obvious" choice for substitution would be

<em>u</em> = <em>y</em> + <em>x</em>

<em>v</em> = <em>y</em> - <em>x</em>

<em />

Solving for <em>x</em> and <em>y</em>, we would have

<em>x</em> = (<em>u</em> - <em>v</em>)/2

<em>y</em> = (<em>u</em> + <em>v</em>)/2

in which case the Jacobian and its determinant are

J=\begin{bmatrix}x_u&x_v\\y_u&y_v\end{bmatrix}=\dfrac12\begin{bmatrix}1&-1\\1&1\end{bmatrix}\implies|\det J|=\left|\dfrac12\right|=\dfrac12

The trapezoid <em>R</em> has two of its edges on the lines <em>x</em> + <em>y</em> = 8 and <em>x</em> + <em>y</em> = 9, so right away, we have 8 ≤ <em>u</em> ≤ 9.

Then for <em>v</em>, we observe that when <em>x</em> = 0 (the lowest edge of <em>R</em>), <em>v</em> = <em>y</em> ; similarly, when <em>y</em> = 0 (the leftmost edge of <em>R</em>), <em>v</em> = -<em>x</em>. So

-<em>x</em> ≤ <em>v</em> ≤ <em>y</em>

-(<em>u</em> - <em>v</em>)/2 ≤ <em>v</em> ≤ (<em>u</em> + <em>v</em>)/2

-<em>u</em> + <em>v</em> ≤ 2<em>v</em> ≤ <em>u</em> + <em>v</em>

-<em>u</em> ≤ <em>v</em> ≤ <em>u</em>

<em />

So, the integral becomes

\displaystyle\iint_R5\cos\left(7\frac{y-x}{y+x}\right)\,\mathrm dA=\int_8^9\int_{-u}^u\frac52\cos\left(\frac{7v}u\right)\,\mathrm dv\,\mathrm du

=\displaystyle\frac52\int_8^9\frac u7(\sin7-\sin(-7))\,\mathrm du

=\displaystyle\frac57\sin7\int_8^9u\,\mathrm du

=\displaystyle\frac5{14}\sin7(9^2-8^2)=\boxed{\frac{85}{14}\sin7}

4 0
3 years ago
Slope (12,-18),(11,12)
olga nikolaevna [1]
If you are trying to find the slope using only these two points then you should first take note of what your X and Y values are. For instance, 12 & 11 are your X values and -18 & 12 are your Y values. Knowing this you can now find your slope by doing y2-y1/
x2-x1. You will get the fraction -30/1 or -30 which is your slope. Hope that made sense!
4 0
3 years ago
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