Answer:
<h3><em>the </em><em>answer</em><em> </em><em>is </em><em>A</em></h3>
Step-by-step explanation:
8x+6is equivalent to-7(1-x)+x+13 because
-7(1-x)+x+13
we use-7to multiply the numbers in the bracket which is equal to -7+7x(minus ❌times minus =+)
-7+7x+x+13
collect like terms
7x+x+13-7=8x+6
answer is A
3kilometers
kilo=100
3kilometers=3000meters
3000 meters=how many times of the track
track=200
3000meters=how many times 200
divide both sidse by 200
15=how many laps
answe ris 15 times
The amount is $510.12 and the interest is $10.12.
Explanation
STEP 1: Convert 120 months into years.
120 months =12012 years=10 years
STEP 2: To find amount we use formula:
A=P(1+rn)n⋅t
A = total amount
P = principal or amount of money deposited,
r = annual interest rate
n = number of times compounded per year
t = time in years
In this example we have
P=$500 , r=0.2% , n=12 and t=10 years
After plugging the given information we have
AAAA=500(1+0.00212)12⋅10=500⋅1.000167120=500⋅1.02024=510.12
STEP 3: To find interest we use formula A=P+I, since A=510.12 and P = 500 we have:
A510.12II=P+I=500+I=510.12−500=10.12
Answer:
0.5781
Step-by-step explanation:
Let 'S' be the dominant allele for solid coat color and 's' be the recessive allele for spotted coat color.
By crossing a homozygous solid-colored dog (SS) with a spotted dog (ss), all of the F1 will present the Ss genotype.
When crossing two F1 dogs, the sample space for F2 is:
F2={Ss,sS,ss,SS}
For each puppy, there is a 1 in 4 chance of having a spotted coat.
The probability that at least one of the three F2 puppies have a spotted coat is 100% minus the probability that none have a spotted coat:
The probability that at least one of the three F2 puppies will have a spotted coat is 0.5781.