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Misha Larkins [42]
3 years ago
8

When a batter hits a ball the impulse is?

Mathematics
1 answer:
Allushta [10]3 years ago
4 0

Answer:

C) The force multiplied by the time the objects are in contact

Impulse = F.Δv

100% sure. Go with it. Hope this helps

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Write the equation of the ellipse using the given information:
horsena [70]

We know, equation of ellipse is given by :

\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1

Here,

(h,k) is centre of the ellipse = (0,0).

a = major axis = 8.

b = minor axis = 4.

Putting all given value in above equation, we get :

\dfrac{(x-0)^2}{8^2}+\dfrac{(y-0)^2}{4^2}=1\\\\\dfrac{x^2}{8^2}+\dfrac{y^2}{4^2}=1\\\\\dfrac{x^2}{64}+\dfrac{y^2}{16}=1

Hence, this is the required solution.

8 0
3 years ago
Bus A leaves the station every 30 mins bus b leaves the station every 20 mins at 10 am both buses leave the station together wor
denis-greek [22]

Answer: 11am

Step-by-step explanation:

To solve this, we have to calculate the lowest common multiple of 20 and 30. This will be:

20 = 20, 40, 60, 80, 100

30 = 30, 60, 90, 120, 150.

Here, the lowest common multiple is 60.

Therefore, we add 60 minutes to 10am. This will be:

= 10am + 1 hour

= 11 am

The next time that both buses leave at the same time would be 11am

3 0
3 years ago
Can I actually get help and not people saying random stuff just for points????
loris [4]
Do you still need it?
8 0
3 years ago
GIVING THE BRAINLIEST ANSWER
Ahat [919]

Answer:

(6,3)

Step-by-step explanation:

y=2/3 x - 1

y=-1/2 x + 6

Since both equations are equal to y, we can set them equal

2/3 x - 1 =-1/2 x + 6

We have fractions, so I will multiply by 6 to clear the fractions

6(2/3 x - 1) =(-1/2 x + 6)6

Distribute

4x -6 = -3x +36

Add 3x to each side

4x+3x -6 = -3x+3x +36

7x -6 = 36

Add 6 to each side

7x-6+6 = 36+6

7x = 42

Divide each side by 7

7x/7 = 42/7

x =6

Now we need to find y

y =2/3x -1

y = 2/3(6) -1

y = 4-1

y=3

(6,3)

5 0
3 years ago
URGENT!! NEED THIS IN TWO HOURS. DUMB ANSWERS WILL BE REPORTED ALTHOUGH I UNDERSTAND IF YOU MAKE A SIMPLE MISTAKE IN YOUR CALCUL
Andre45 [30]

Yo sup??

The given points are (1,1),(1,3) and (9,2)

equation of circle is

8x²+8y²+ax+by=0

let us plug in (1,1) in the equation we get

8+8+a+b=0

a+b=-16

let us now plug in (1,3) in the equation

8+8*3²+a+3b=0

a+3b=-80

let us. now solve the two equation in terms of a and b

we get

2b=--64

b=-32

and

a=-16+32

=16

therefore the equation is

8x²+8y²+16x-32y=0

Hope this helps

6 0
3 years ago
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