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3 years ago

14

Jessie is 6 years older than Todd, and Todd is 2 years younger than Ryan. If Ryan is r years old, which expression shows how old

Jessie is?

1 answer:

mariarad [96]3 years ago

6 0

Jessie = Todd + 6
Todd = Ryan -2

if Ryan = r
so Todd = r-2
then Jessie = (r-2) + 6 = r-4 years old

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Evaluate: (d + 1)(d - 1 + 6) <br> d = 2

Allisa [31]

F(d)=(d+1)(d-1+6)
f(d)=(d+1)(d+5)
f(2)=(2+1)(2+5)
f(2)=(3)(7)
f(2)=21

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3 years ago

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Answer:

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explanation:

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3 years ago

Flora is making salsa for a party. Every 1 cup of chopped tomatoes makes 2 3/4 cups of salsa. She uses 1 2/3 cups of tomatoes. H

pogonyaev

Answer:

4 $\frac{7}{12}$ cups of Salsa.

Step-by-step explanation:

Flora is making Salsa for a party.

Every 1 cup of chopped tomatoes makes 2 $\frac{3}{4}$ = $\frac{11}{4}$ cups of Salsa

She uses 1 $\frac{2}{3}$ = $\frac{5}{3}$ cups of tomatoes

1 $\frac{2}{3}$ cups of tomatoes makes:

$\frac{5}{3}$ × $\frac{11}{4}$ ÷ 1 = $\frac{55}{12}$ = 4 $\frac{7}{12}$ cups of Salsa.

5 0

3 years ago

Finish labeling the number of elements in the regions in the Venn diagram shown to the right, where the subsets

Virty [35]

Answer:

t=14

v=13

q=12

s=23

w=-4

x=28

Step-by-step explanation:

we know that the universal set =100

so, everything in it must add up to 100

first, from the information given to us,

t= n(A n C)= 14

v=n(B n C)= 13

to find q

we know from our guide that n(A) =40

which means everything inside A will add up to 40

therefore,

q + 7 + 7 + t = 40

and we already know that t = 14

so, that will be;

q + 7 + 7 + 14 = 40

therefore, q = 12

to find s,

we all know that n(B) = 50

which means that everything inside B will be equal to 50

therefore,

s + 7 + 7 + v = 50

and we know that v = 13

therefore,

s + 7 + 7 + 13 = 50

and s will end up to be = 23

to find w,

we know that n(C) = 30

so, everything in C end up to be all equal to 30

therefore,

t + 7 + w + v = 30

from our solution, t = 14, v = 13

so,

14 + 7 + w

4 0

3 years ago

Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v

k0ka [10]

I'll use subscript notation for brevity, i.e. $\frac{\partial f}{\partial x}=f_x$ .

By the chain rule,

$z_u=z_xx_u+z_yy_u$

$z_v=z_xx_v+z_yy_v$

$z_w=z_xx_w+z_yy_w$

We have

$z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}$

and

$\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}$

When $u=1,v=1,w=0$ , we have

$\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}$

and the partial derivatives take on values of

$\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}$

So we end up with

$\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}$

3 0

3 years ago