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Ann [662]
2 years ago
9

A photographer has a print that is 3.5 inches wide and 2.5 inches tall. If the photographer enlarges the print so that it is 7 i

nches wide, how tall will it be?
5 inches
6 inches
8 inches
12 inches
Mathematics
2 answers:
Crank2 years ago
8 0
B. if it is 7 inches wide it will be 6 inches tall
Vinil7 [7]2 years ago
6 0

Answer:

5 inches

Step-by-step explanation:

Hope I helped

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can someone help me answer a trigonometry question? I'm new to this website so I don't know how to write my question out
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maybe you can attach the photo ?

5 0
3 years ago
Which one is equivalent to the problem ? please help me!!!
lesya692 [45]

Answer:

B

Step-by-step explanation:

This is a power to a power problem. -3 times 2 equals-6. Usually when a number is raised to a negative power, the number is the denominator over 1...with the exponent in the denominator ad well. 5 to the -6 power is 15,605 which is the same as 1/5 to the 6th power....1/15,605

5 0
3 years ago
Find a power series representation of e^x sin(x)
liberstina [14]
The Taylor series is defined by:
f(x) = \sum \frac{f^n (a)}{n!} (x-a)^n

Let a = 0.
Then its just a matter of finding derivatives and determining how many terms is needed for the series.

Derivatives can be found using product rule:
f^n (x) = e^x g^{n-1} (x) + e^x g^n (x)  \\ g^0 (x) = sin x

Do this successively to n = 6.
f^1 (x) = e^x (sinx +cos x) \\ f^2 (x) = e^x (2cos x)  \\ f^3 (x) = e^x(2cos x - 2sin x)  \\ f^4 (x) = e^x (-4 sin x)  \\ f^5 (x) = e^x(-4sinx -4cos x) \\ f^6(x) = e^x(-8cos x)

Plug in x=0 and sub into taylor series:
e^x  sin x = x+x^2 +\frac{x^3}{3} -\frac{x^5}{30}-\frac{x^6}{90}...

If more terms are needed simply continue the recursive derivative formula and add to taylor series.
6 0
3 years ago
Solve the systems by elimination: <br><br> 8x-2y= -10<br> -4x+y= 5
Pachacha [2.7K]

Let's eliminate x.  To achieve this, mult. the 2nd equation by 2, obtaining

-8x + 2y = 10.  Now add this result to the first equation:

8x-2y= -10

-8x + 2y = 10

---------------------

        0

The two equations actually represent the same line.   Without an x- or a y-value, we cannot solve for the value of the other variable.  There are infinitely many solutions.

--------------------



4 0
3 years ago
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