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Allisa [31]
3 years ago
14

What is the y-intercept of the line given by the equation y= 3x + 4?

Mathematics
2 answers:
DIA [1.3K]3 years ago
8 0

Answer:

the y intercept is 4

Step-by-step explanation:

the 4 is where the line starts so it would be (0,4)

Alik [6]3 years ago
8 0

First, notice that this equation is written in slope-intercept form which is more commonly known as y = mx + b form where the multiplier, m, or the coefficient of the ex term represents the slope of the line and the <em>b</em> or the constant term represents the y-intercept of the line.

I have attached slope-intercept form below.

Notice that below, the <em>b</em> is in place of the <em>4</em> in the equation.

So the y-intercept or the <em>b</em> is 4.

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Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

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22 because you take the smallest and largest number and subtract them so you do 81-59=22
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