14 x² + 6 x - 7 x - 3 =
= ( 14 x² - 7 x ) + ( 6 x - 3 ) =
= 7 x ( 2 x - 1 ) + 3 ( 2 x - 1 ) =
= ( 2 x - 1 ) ( 7 x + 3 )
Answer:
1. GCF of the group ( 6 x - 3 ) is 3.
2. The common binomial factor is 2 x - 1.
3. The factored expression is: ( 2 x - 1 ) ( 7 x + 3 ).
If Susan had 2$ and got to 12$ we need to find what multiplied by 2 = 12. So, 12/2=6
If 6x2=12 then 11x6=66
66$
<span>The correct answer is option B. i.e. Both equation 1 and 2 have the same number of solutions. The equation 1 is |5x+6| = 41 By removing the modulus sign we get, 5x + 6 = 41 and 5x +6 = -41. Solving, 5x = 6 = 41 we get, 5x = 35 or x = 7. And, on solving 5x +6 = -41 we get, 5x = -47 or x = 9.4 Now. the second equation is |2x+13| = 28 By removing the modulus sign we get, 2x+ 13 = 28 and 2x +13 = -28. Solving, 2x = 28 -13 = 15 or x = 7.5 . And, on solving 2x +13 = -28 we get, 2x = -41 or x = -20.5.TH </span>
I believe it’s 5, 2 you would just you 2,-2 as a line segment
The middle number is 0 and the last is -81Factoring means we want something like(b+_)(b+_)We need two numbers that add together to get and Multiply to get -81which are 9 and -9:<span><span>9+-9 = 0 and </span><span>9*-9 = -81</span></span>
Fill in the blanks in
(b+_)(b+_)
with 9 and -9 to get...<span><span>(<span>b+9</span>)</span><span>(<span>b−9</span>)</span></span>
The answer is : (b+9)(b−9)
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