Think about the SSS Congruence Postulate. Why do you think it is a postulate and not a theorem?

Need help on this math problem!!!

Colt1911 [192]

Answer:

$(fof^{-1})(x)=x$

Step-by-step explanation:

Composition of two functions f(x) and g(x) is represented by,

(fog)(x) = f[g(x)]

If a function is,

f(x) = (-6x - 8)² [where x ≤ $-\frac{8}{6}$ ]

Another function is the inverse of f(x),

$f^{-1}(x)=-\frac{\sqrt{x}+8}{6}$

Now composite function of these functions will be,

$(fof^{-1})(x)=f[f^{-1}(x)]$

= $[-6(\frac{\sqrt{x}+8}{6})-8]^{2}$

= $[-\sqrt{x}+8-8]^2$

= $(-\sqrt{x})^2$

= x

Therefore, $(fof^{-1})(x)=x$

4 0

2 years ago

What is percent probability

svetlana [45]

The probability would be 9/12 or 3/4 in the lowest form

7 0

3 years ago

under a dilation, the point (2,6) is moved to (6,18) what is the scale factor of the dilation? enter your answer in the box

Anestetic [448]

Step-by-step explanation:

The equation of line passing through the two points is $\frac{y-y_{1} }{x-x_{1} }=\frac{y_{2} -y_{1}}{x_{2} -x_{1}}$

When substituted,the equation becomes $\frac{y-6}{x-2}=\frac{18-6}{6-2}$

which when simplified is $y=3\times x$

The line clearly passes through origin.

The distance between two points is $\sqrt{(y_{1}-y_{2} )^{2}+(x_{1}- x_{2} )^{2}}$

Distance between origin and $(2,6)$ is $\sqrt{40}$ .

Distance between origin and $(6,18)$ is $\sqrt{360}$

Scale factor is $\frac{distance\text{ }of\text{ }p_{2}\text{ from origin}}{distance \text{ } of \text{ } p_{1}\text{ from origin}}$

So,scale factor is $\frac{\sqrt{360} }{\sqrt{40} }$

which when simplified becomes 3.

6 0

2 years ago

X-y=6<br> 2x-3z=16<br> 2y+z=4<br><br> Solve the systems of equations.

Neko [114]

Answer:

Given System of equation:

x-y =6 .....,[1]

2x-3z = 16 ......[2]

2y+z = 4 .......[3]

Rewrite the equation [1] as

y = x - 6 .......[4]

Substitute the value of [4] in [3], we get

$2(x-6)+z = 4$

Using distributive property on LHS ( i.e, $a \cdot (b+c) =a \cdot b+ b \cdot c$ )

then, we have

2x - 12 +z =4

Add 12 to both sides of an equation:

2x-12+z+12=4+12

Simplify:

2x +z = 16 .......[5]

On substituting equation [2] in [5] we get;

2x+z=2x -3z

or

z = -3z

Add 3z both sides of an equation:

z+3z = -3z+3z

4z = 0

Simplify:

z = 0

Substitute the value of z = 0 in [2] to solve for x;

$2x-3(0) = 16$

or

2x = 16

Divide by 2 both sides of an equation:

$\frac{2x}{2} =\frac{16}{2}$

Simplify:

x= 8

Substitute the value of x =8 in equation [4] to solve for y;

y = 8-6 = 2

or

y = 2

Therefore, the solution for the given system of equation is; x = 8 , y = 2 and z =0

5 0

3 years ago

assume that at+tu=su the ratio between the lengths of st and tu is 1:3 if su has a length of 148 find the value of tu

g100num [7]

1cm=10mm 700mm= 70cm 600mm=60cm 70cm:25cm=2,8 - on length only 2 fit into 60cm:25=2,4 - on width only 2 fit into Two 25cm in diameter fit into the baking tray.

6 0

2 years ago