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Ira Lisetskai [31]
3 years ago
14

Six less than twice a number, x, is 38. What is the value of x? 76 16 70 22

Mathematics
1 answer:
uranmaximum [27]3 years ago
4 0

Answer:

22

Step-by-step explanation:

2x -6 = 38

Add 6 to each side

2x-6+6 = 38+6

2x + 44

Divide each side by 2

2x/2 = 44/2

x = 22

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Find the length of a photograph whose width is 10 inches and whole proportions are the same as a 5-inch by 8-inch photograph.
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5 inch is the width, 8 inch is the length.

Find to scale between the two widths:

10 /5 = 2 the larger photo is 2 times larger,

Multiply the known length by 2:

8 x 2 = 16

The length would be 16

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4032 integers.

Step-by-step explanation:

Lest start with -2016. There are 2016 integers from -2016 to 0. Then we see how many integers are from 0 to 2016. there are 2016. If you add them up, you get 4032.

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a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
3 years ago
The Wonderful Widget Company's earnings have declined to the point where they need to reduce the number of employees from 1500 1
AleksandrR [38]

Answer:6%

Step-by-step explanation:

Decrease = 1500 - 1410= 90

% decrease = (90/1500)*100%

= 6%

7 0
3 years ago
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