The upper deck at a baseball stadium has produced, among other complaints, displeasure with its steepness. It is 200 ft from h
1 answer:
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Answer: B. H(t) = -6.9(t - 2.3)² + 112
<u>Step-by-step explanation:</u>
The vertex form of a quadratic equation is: y = a(x - h)² + k
where (h, k) is the vertex ⇒ k is the maximum height
the distance traveled is when y = 0 ⇒
Given: H(t) = -7.1(t - 2.3)² + 98
maximum height (k) = 98 feet
distance traveled (x) = = 6.02 seconds
A) H(t) = -7.5(t - 2.2)² + 112
maximum height (k) = 112 feet
distance traveled (x) = = 6.06 seconds
B) H(t) = -6.9(t - 2.3)² + 112
maximum height (k) = 112 feet
distance traveled (x) = = 6.33 seconds
C) H(t) = -6.9(t - 2.4)² + 95
maximum height (k) = 95 feet
This has a lower height than the given equation.
D) H(t) = -7.5(t - 2.3)² + 95
maximum height (k) = 95 feet
This has a lower height than the given equation.
Both options A and B travel higher and stay in the air longer than last year's winner, however option B stays in the air longer than option A.
Answer:
The value of the expression increases as j decreases
Step-by-step explanation:
Let
As j decreases, the value of j300 decreases (i.e the farther j300 is from 150). Due to the wider gap between 150 and j300, the value of f(j) increases.
For example:
When j = 1, f(j) = 150 - (300*1) = -150
When j = 0.5, f(j) = 150 - (300*0.5) = 0
When j = 0. f(j) = 150 - (300*0) = 150
It is obvious from the analogy above that the expression 150-j150−j150 increases as j decreases