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a) The point-slope form of the equation of a line through point (h, k) with slope m is
y - k = m(x - h)
In point-slope form, the equation of the line through (-3, -7) with slope -6/5 is
y + 7 = (-6/5)(x + 3)
b) The graph of
y = |x|-4
represents a translation downward 4 units of the graph of
y = |x|
It retains the same general shape and axis of symmetry, but will have two (2) x-intercepts instead of one (1).
y - k = m(x - h)
In point-slope form, the equation of the line through (-3, -7) with slope -6/5 is
y + 7 = (-6/5)(x + 3)
b) The graph of
y = |x|-4
represents a translation downward 4 units of the graph of
y = |x|
It retains the same general shape and axis of symmetry, but will have two (2) x-intercepts instead of one (1).
Since we want to find the value of <em>k</em><em> </em>where the limit exists, set both equations equal to each other. Then substitute <em>x</em> = -1 in for each equation to find <em>k</em><em>.</em>
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1. Set both equations equal.
2. Substitute <em>x</em><em> </em>= -1.
3. Solve for <em>k</em><em> </em>by adding <em>k</em><em> </em>to both sides. Continue the process of solving the equation.
Thus, <em>k</em><em> </em>= -2. Check by graphing the function.