answer with an example is attached below
Yes
remember you can do anything to an equaiton as long as you do it to boh sides
ad try to get unknown to one side
9n-10=4n+10
minus 4n both sides
9n-4n-10=4n-4n+10
5n-10=0+10
add 10
5n+10-10=0+10+10
5n+0=20
5n=20
divide both sies by 5
5n/5=20/5
5/5n=4
1n=4
n=4
Answer:
Please make it a bit bigger.
Step-by-step explanation:
I can't see it
Let's simplify step-by-step.
<span><span>12<span>x^2</span></span>+<span>9<span>x^2
</span></span></span>Combine Like Terms:
<span>=<span><span>12<span>x^2</span></span>+<span>9<span>x^2
</span></span></span></span><span>=<span>(<span><span>12<span>x^2</span></span>+<span>9<span>x^2</span></span></span>)
</span></span><span>=<span>21<span>x^<span>2</span></span></span></span>
CONSECUTIVE NUMBERS; x, x+1
(x+1)4=3(x)+23
4x+4=3x+23
4x-3x=23-4
x=19
x+1=20
THEREFORE the consecutive numbers are 19&20
