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3 years ago

I’m really confused could someone help me?

Mathematics

2 answers:

Vilka [71]3 years ago

8 0

Answer:

The answer to your question is: a and b are solutions,

96 crackers

Step-by-step explanation:

a) (4, 0)

y = x - 4

0 = 4 -4

0 = 0 It's a solution

b) (3, -1)

y = x - 4

-1 = 3 - 4

-1 = -1 It's a solution

c) (6, 3)

y = x - 4

3 = 6 - 4

3 = 2 It's not a solution

d) (2, -4)

y = x - 4

-4 = 2 - 4

-4 = -2 It's not a solution

Second question, 96 crackers

8 crackers ------------------- 1 serving

x --------------------- 12 serving

x = (12 x 8) / 1

x = 96 crackers

GenaCL600 [577]3 years ago

6 0

Answer:

B and C

Step-by-step explanation:

4,0 x=4 y=x-4=0

3,-1 x=4 y=x-4=-1

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PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!

marishachu [46]

Answer:

32m^2

Step-by-step explanation:

32m^2

8*4 = 32

Have a nice day! :-)

6 0

3 years ago

Evaluate 5(x - 1) - 2 when x = 3. O A. -4 Ос. O D.O

12345 [234]

Answer:

Step-by-step explanation

First you have to plug in 3 for x:

5(3-1)-2

Then using PEMDAS you would simplify that:

5(2)-2

10-2

4 0

3 years ago

Which of the following gives a single solution of the |x+3|- 2

topjm [15]

Answer:

x=-1

Step-by-step explanation:

given $\left | x+3 \right |$ -2=0

$\left | x+3 \right |$ =2

x+3=+2

x=-1, also, x+3=-2

x=-2-3=-5

hence x=-1 , -5 answer

6 0

3 years ago

The population of a community is known to increase at a rate proportional to the number of people present at time t. If the popu

Lady bird [3.3K]

Answer:

$P(t) = P(0)e^{0.0693t}$

Step-by-step explanation:

The population of a community is known to increase at a rate proportional to the number of people present at time t.

This means that the population growth is modeled by the following differential equation:

$\frac{dP(t)}{dt} = rP(t)$

Which has the following solution:

$P(t) = P(0)e^{rt}$

In which P(t) is the population after t years, P(0) is the initial population and r is the growth rate.

The population has doubled in 10 years

This means that $P(10) = 2P(0)$ . We use this to find r.

$P(t) = P(0)e^{rt}$

$2P(0) = P(0)e^{10r}$

$e^{10r} = 2$

$\ln{e^{10r}} = \ln{2}$

$10r = \ln{2}$

$r = \frac{\ln{2}}{10}$

$r = 0.0693$

So the equation that will estimate the population of the community in t years is:

$P(t) = P(0)e^{0.0693t}$

6 0

3 years ago

A 95% confidence interval for a population proportion was constructed using a sample proportion from a random sample. Which of t

liraira [26]

Answer:

All but last statement are correct.

Step-by-step explanation:

If we were to use a 90% confidence level, the confidence interval from the same data would produce an interval wider than the 95% confidence interval.

True. Confidence interval gets wider as the confidence level decreases.

The sample proportion must lie in the 95% confidence interval.

True. Confidence interval is constructed around sample mean.

There is a 95% chance that the 95% confidence interval actually contains the population proportion.

True. Constructing 95%. confidence interval for a population proportion using a sample proportion from a random sample means the same as the above statement.

We don't know if the 95% confidence interval actually does or doesn't contain the population proportion

True. There is 95% chance that confidence interval contains population proportion and 5% chance that it does not.

The population proportion must lie in the 95% confidence interval

False. There is 95% chance that population proportion lies in the confidence interval.

5 0

3 years ago