Answer:
I'm not entirely sure but I think that what is says is that it wants you to find the value of x in (4x+28) to make it 116 degrees because it is that same angle. So what you do is you get (4x+28)=116 and you do this because they are the same angle so you use 116 and get it to solve x. Since I'm lazy, then I go to this website and type the equation in: m a t h w a y . c o m but without all of the spaces, I had to do that so it would let me answer this, but I'll do it the real way this time. (4x+28)=116 Their is a rule in math that as long as you do something to one side of the equal sign in the equation, you have to do it to the other and it will still work. So, you minus 28 from both sides so that you can get rid of it and you now have 4x=88. Now you should know this part but you divide 4 from both sides to make so x is alone. Now you have x=22 because you divided 4 from each side. So their is your answer: x=22.
Step-by-step explanation: If you have the answer key that you can check from to make sure you got it right because I know some teachers let you do that, then you should make sure that is right, but I am pretty sure it is.
Answer: 20 feet perimeter is the largest allowed
Step-by-step explanation: width=2.5 length=no more than 3x2.5
so find longest possible length allowed...
2.5x3=7.5
calculate largest perimeter allowed...
2(7.5+2.5)=20
Answer:
R(-3, 8)
Step-by-step explanation:
R = 2Q -P
R = 2(4, 3) -(11, -2) = (8-11, 6+2)
R = (-3, 8)
_____
You can derive the formula for the endpoint from the formula for the midpoint:
Q = (R + P)/2
R = 2Q - P . . . . . . multiply by 2 and subtract P
#3
2 and three are supplementary angles .
#4.
The answer is opposite angles .
#5
Bisected angles are equal
Now
m<ABC
<h3>x²+5x+3+2x²+10x15 =0</h3><h3>x²+2x²+5x+10x+3+15=0</h3><h3>3x²+15x+18=0</h3><h3>3(x²+5x+6) =0 because 3 is common factor</h3><h3>3(x²+3x+2x+6) spill the middle term</h3><h3>3(x(x+3)+2(x+3) take the common factor from term</h3><h3>3(x+2) (x+3)</h3>
<h3>answer is 3(x+2) (x+3)</h3>
please mark this answer as brainlist
