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gayaneshka [121]
3 years ago
5

Anna wants to rent movies from either Service A or Service B. Service A charges $37.92 as a subscription fee with a charge of $2

.18 per movie. Service B charges $33.25 as a subscription fee plus $3.55 per movie. Service B is running a special offer where the first movie is free. Given that Anna always rents at least 1 movie in a given subscription period, how many movies would she have to rent for the average cost per movie to be equal at Service A or Service B?
Mathematics
2 answers:
goldenfox [79]3 years ago
7 0
I think it is $76.80
Paha777 [63]3 years ago
4 0

Answer: 6 movies

Step-by-step explanation:Service A

1. $37.92 +&2.18=$40.1

2. $41.1+$2.18=$42.28

3....

4....

5....

6. $48.82+$2.18=$51

Service B

1. $33.25+free movie=$33.25

2. $33.25+$3.55=$36.8

3....

4....

5....

6. $47.45+$3.55=$51


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Hello from MrBillDoesMath!

Answer:

n = 5


Discussion:

Let the original number be "n"  Translating the problem  statement to mathematical symbolism:

n + 4 = 19 - 2n                   =>  add 2n to both sides

n + 2n + 4 = 19 - 2n + 2n  =>  combine like terms

3n + 4 = 19                        => subtract 4 from both sides

3n = 19 -4  = 15                 => divide both sides by 3

n = 15/3 =5


Check: Does 5 +4 = 19 - 2(5)? Does 9 = 9? Yes. so the value for n is confirmed correct.


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