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gayaneshka [121]
2 years ago
5

Anna wants to rent movies from either Service A or Service B. Service A charges $37.92 as a subscription fee with a charge of $2

.18 per movie. Service B charges $33.25 as a subscription fee plus $3.55 per movie. Service B is running a special offer where the first movie is free. Given that Anna always rents at least 1 movie in a given subscription period, how many movies would she have to rent for the average cost per movie to be equal at Service A or Service B?
Mathematics
2 answers:
goldenfox [79]2 years ago
7 0
I think it is $76.80
Paha777 [63]2 years ago
4 0

Answer: 6 movies

Step-by-step explanation:Service A

1. $37.92 +&2.18=$40.1

2. $41.1+$2.18=$42.28

3....

4....

5....

6. $48.82+$2.18=$51

Service B

1. $33.25+free movie=$33.25

2. $33.25+$3.55=$36.8

3....

4....

5....

6. $47.45+$3.55=$51


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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%
ivolga24 [154]

Answer:  

<em>a.  The system of equations that models the situation is....</em>

<em>     0.80x+0.50y=3.60\\\\ 0.20x+0.50y=2.40</em>

<em>b.  The solution to the system:  x = 2 and y = 4 </em>

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Step-by-step explanation:

Suppose, the amount of 80/20 mixture is  x pounds and the amount of 50/50 mixture is  y pounds.

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And the amount of peanuts in 50/50 mixture =0.50y pound and the amount of almonds in 50/50 mixture =0.50y pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture =(6\times 0.60)=3.60 pounds

and the amount of almonds in that mixture =(6 \times 0.40)= 2.40 pounds.

So, the system of equations will be.........

0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)

Subtracting equation (2) from equation (1), we will get.....

(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2

Now, plugging this x=2 into equation (1), we will get......

0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

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