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gayaneshka [121]
3 years ago
5

Anna wants to rent movies from either Service A or Service B. Service A charges $37.92 as a subscription fee with a charge of $2

.18 per movie. Service B charges $33.25 as a subscription fee plus $3.55 per movie. Service B is running a special offer where the first movie is free. Given that Anna always rents at least 1 movie in a given subscription period, how many movies would she have to rent for the average cost per movie to be equal at Service A or Service B?
Mathematics
2 answers:
goldenfox [79]3 years ago
7 0
I think it is $76.80
Paha777 [63]3 years ago
4 0

Answer: 6 movies

Step-by-step explanation:Service A

1. $37.92 +&2.18=$40.1

2. $41.1+$2.18=$42.28

3....

4....

5....

6. $48.82+$2.18=$51

Service B

1. $33.25+free movie=$33.25

2. $33.25+$3.55=$36.8

3....

4....

5....

6. $47.45+$3.55=$51


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Explanation:


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Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
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\text{z-score} = \frac{x - \mu}{\sigma}
\\
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\\
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Let

t = time for the auditor to finish his work
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Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) 
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Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
3 years ago
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