1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gayaneshka [121]
2 years ago
5

Anna wants to rent movies from either Service A or Service B. Service A charges $37.92 as a subscription fee with a charge of $2

.18 per movie. Service B charges $33.25 as a subscription fee plus $3.55 per movie. Service B is running a special offer where the first movie is free. Given that Anna always rents at least 1 movie in a given subscription period, how many movies would she have to rent for the average cost per movie to be equal at Service A or Service B?
Mathematics
2 answers:
goldenfox [79]2 years ago
7 0
I think it is $76.80
Paha777 [63]2 years ago
4 0

Answer: 6 movies

Step-by-step explanation:Service A

1. $37.92 +&2.18=$40.1

2. $41.1+$2.18=$42.28

3....

4....

5....

6. $48.82+$2.18=$51

Service B

1. $33.25+free movie=$33.25

2. $33.25+$3.55=$36.8

3....

4....

5....

6. $47.45+$3.55=$51


You might be interested in
Divide 36087 by 56 and verify the result by division algorithm.​
patriot [66]

Answer:

Do like this

Step-by-step explanation:

Hope it helps you

5 0
2 years ago
Consider the following function.
Kryger [21]

Answer:

See below

Step-by-step explanation:

I assume the function is f(x)=1+\frac{5}{x}-\frac{4}{x^2}

A) The vertical asymptotes are located where the denominator is equal to 0. Therefore, x=0 is the only vertical asymptote.

B) Set the first derivative equal to 0 and solve:

f(x)=1+\frac{5}{x}-\frac{4}{x^2}

f'(x)=-\frac{5}{x^2}+\frac{8}{x^3}

0=-\frac{5}{x^2}+\frac{8}{x^3}

0=-5x+8

5x=8

x=\frac{8}{5}

Now we test where the function is increasing and decreasing on each side. I will use 2 and 1 to test this:

f'(2)=-\frac{5}{2^2}+\frac{8}{2^3}=-\frac{5}{4}+\frac{8}{8}=-\frac{5}{4}+1=-\frac{1}{4}

f'(1)=-\frac{5}{1^2}+\frac{8}{1^3}=-\frac{5}{1}+\frac{8}{1}=-5+8=3

Therefore, the function increases on the interval (0,\frac{8}{5}) and decreases on the interval (-\infty,0),(\frac{8}{5},\infty).

C) Since we determined that the slope is 0 when x=\frac{8}{5} from the first derivative, plugging it into the original function tells us where the extrema are. Therefore, f(\frac{8}{5})=1+\frac{5}{\frac{8}{5}}-\frac{4}{\frac{8}{5}^2 }=\frac{41}{16}, meaning there's an extreme at the point (\frac{8}{5},\frac{41}{16}), but is it a maximum or minimum? To answer that, we will plug in x=\frac{8}{5} into the second derivative which is f''(x)=\frac{10}{x^3}-\frac{24}{x^4}. If f''(x)>0, then it's a minimum. If f''(x), then it's a maximum. If f''(x)=0, the test fails. So, f''(\frac{8}{5})=\frac{10}{\frac{8}{5}^3}-\frac{24}{\frac{8}{5}^4}=-\frac{625}{512}, which means (\frac{8}{5},\frac{41}{16}) is a local maximum.

D) Now set the second derivative equal to 0 and solve:

f''(x)=\frac{10}{x^3}-\frac{24}{x^4}

0=\frac{10}{x^3}-\frac{24}{x^4}

0=10x-24

-10x=-24

x=\frac{24}{10}

x=\frac{12}{5}

We then test where f''(x) is negative or positive by plugging in test values. I will use -1 and 3 to test this:

f''(-1)=\frac{10}{(-1)^3}-\frac{24}{(-1)^4}=-34, so the function is concave down on the interval (-\infty,0)\cup(0,\frac{12}{5})

f''(3)=\frac{10}{3^3}-\frac{24}{3^4}=\frac{2}{27}>0, so the function is concave up on the interval (\frac{12}{5},\infty)

The inflection point is where concavity changes, which can be determined by plugging in x=\frac{12}{5} into the original function, which would be f(\frac{12}{5})=1+\frac{5}{\frac{12}{5}}+\frac{4}{\frac{12}{5}^2 }=\frac{43}{18}, or (\frac{12}{5},\frac{43}{18}).

E) See attached graph

5 0
2 years ago
The local ice cream shop surveyed their costumers to see wich flavor of ice cream is most popular.125 people chose chocolate as
svlad2 [7]

Answer: The total costumers were surveyed = 500

Step-by-step explanation:

Let x = total costumers were surveyed.

Given : 125 people chose chocolate as their favorite flavor, which represents 25% of the costumers surveyed.

25% of x = 125

\Rightarrow\ \dfrac{25}{100}\times x = 125\\\\\Rightarrow\ \dfrac{1}{4}x=125\\\\\Rightarrow\ x=125\times4\\\\\Rightarrow\ x= 500

Hence, the total costumers were surveyed = 500

8 0
2 years ago
7x X 8
Nitella [24]
Use basic multiplication: 7x (8) = 56x
or 7(8) x = 56x
5 0
2 years ago
Mr. broun paid $3.30 in tax on a $55 motel bill. What percent of $55 was the Tax?
Bumek [7]

Answer:

That would be 6%.

4 0
3 years ago
Read 2 more answers
Other questions:
  • 1. The cost of 2 pounds of potatoes is $3.78. What is
    15·2 answers
  • Sixty percent of eighth graders at the new middle school ride a bus to school.If 228 8th graders ride the bus to school,how many
    15·2 answers
  • Pls help meh need help
    11·2 answers
  • On a coordinate plane, a rectangle has points K prime (1, 3), L prime (2, 3), M prime (2, negative 3), N prime (1, negative 3).
    12·2 answers
  • Which expression could be modeled by decimal grid?
    13·1 answer
  • 4(3x + 4) - 2x = 24<br> PLSS answer
    13·1 answer
  • Ella is putting her savings into a retirement fund that will compound her $7000 semiannually at 7% interest. How much will her r
    10·1 answer
  • Find the quotient of these complex numbers.
    10·1 answer
  • Hurry please!!!!
    12·2 answers
  • If the fraction 414/x-10 is equivalent to -23 ​, find the value of x. Show your work. Use reasoning to find x.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!