In a right triangle the length of a hypotenuse is 6 and the length of one leg is 5. Find the length of the other leg,

Mathematics

2 answers:

ludmilkaskok [199]3 years ago

7 0

Answer:

sqrt 11

Step-by-step explanation:

Pythagorean theorem again. a^2+b^2=c^2. The hypotenuse is the c value. One of the legs is either a or b, doesn't matter which. So you can make the equation 5^2+b^2=6^2. 25+b^2=36. Subtract 25 from each side to isolate the b variable. You're left with b^2=11. Now you take the square root of each side to get b. This makes b= sqrt 11.

nevsk [136]3 years ago

5 0

Answer:

sqrt 11

Step-by-step explanation:

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The average amount of a beverage in randomly selected 16-ounce beverage can is 16.18 ounces with a standard deviation of 0.4 oun

Artist 52 [7]

Answer:

The probability that the mean of this sample is less than 16.1 ounces of beverage is 0.0537.

Step-by-step explanation:

We are given that the average amount of a beverage in randomly selected 16-ounce beverage can is 16.18 ounces with a standard deviation of 0.4 ounces.

A random sample of sixty-five 16-ounce beverage cans are selected

Let $\bar X$ = sample mean amount of a beverage

The z-score probability distribution for the sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean amount of a beverage = 16.18 ounces

$\sigma$ = standard deviation = 0.4 ounces

n = sample of 16-ounce beverage cans = 65

Now, the probability that the mean of this sample is less than 16.1 ounces of beverage is given by = P( $\bar X$ < 16.1 ounces)

P( $\bar X$ < 16.1 ounces) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{16.1-16.18}{\frac{0.4}{\sqrt{65} } }$ ) = P(Z < -1.61) = 1 - P(Z $\leq$ 1.61)