Answer:
12
Step-by-step explanation:
10x-11+3x-2+3x+1=180
16x-12=180
16x=192
x=12
The <em>xy</em>-plane has a normal vector of 〈0, 0, 1〉, and any plane parallel to it will have the same normal vector.
Then the equation of the plane through (6, 3, 2) that is parallel to the <em>xy</em>-plane has equation
〈<em>x</em> - 6, <em>y</em> - 3, <em>z</em> - 2〉 • 〈0, 0, 1〉 = 0
==> <em>z</em> - 2 = 0
==> <em>z</em> = 2
Answer:
38.957625 US$
Step-by-step explanation:
38.957625 US$
Answer:
Step-by-step explanation:
∫tan(x)dx∫cot(x)dx∫sec(x)dx∫csc(x)dx====−ln∣∣cos(x)∣∣+C=ln∣∣sec(x)∣∣+Cln∣∣sin(x)∣∣+C=−ln∣∣csc(x)∣∣+Cln∣∣sec(x)+tan(x)∣∣+C−ln∣∣csc(x)+cot(x)∣∣+C