All categories

3 years ago

Find the solution set for this equation M^2-4=0

Mathematics

1 answer:

Helga [31]3 years ago

5 0

Step-by-step explanation:

Hey, there !!

Let's simply work with it,...................

Here, theequation is,

${m }^{2} - 4 = 0$

$or \: {m }^{2} = 4$

$or \: m = + - \sqrt{4}$

$or \: m = + - \sqrt{ {2}^{2} }$

cancelling square and square root we get answer is,

= (+ - 2).

It means the value of m is plus(+) minus(-) 2.

<em>Hope</em><em> </em><em>it helps</em><em>.</em><em>.</em><em>.</em>

You might be interested in

A builder purchases 600 bricks for a new residential construction. The dimensions of each brick are 5.1 cm by 10.2 cm by 20.3 cm

Blababa [14]

<h3>Answer:</h3>

1165.83 kg

<h3>Explanation:</h3>

The total mass is the product of volume of one brick, the number of bricks, and the density. For this problem, it is convenient to use dimensions in meters.

$(0.051\,m)(0.102\,m)(0.203\,m)(600)\dfrac{1840\,kg}{m^3}=(0.6336036\,m^3)\dfrac{1840\,kg}{m^3}\\\\=1165.83\,kg$

6 0

3 years ago

Read 2 more answers

I WILL GIVE BRAINLIEST Given: BFCE, AB perpendicular to BE, DE perpendicular to BE,

mars1129 [50]

Answer:

Step-by-step explanation:

From the given picture,

∠ABE = ∠DEF = 90° [Since, AB and DE are perpendicular to DE]

m∠ECA = m∠BFD [Given]

m∠ECA + m∠ACB = 180° [Liner pair of angles]

m∠BFD + m∠DFE = 180° [Liner pair of angles]

m∠ACB + m∠ECA = m∠BFD + m∠DFE [Transitive property]

m∠ACB = m∠DEF [Since, m∠ECA = m∠BFD]

Therefore, ΔABC ≅ ΔDEF [By AA property of similarity]

3 0

2 years ago

(50 points) Which graph is defined by the function given below?

marta [7]

Answer:

Graph B

Step-by-step explanation:

y = (x - 3)(x - 3)

The x intercepts are at 3

Since both intercepts are at 3, the vertex is at 3

We know it is an upwards facing parabola since it is quadratic and the constant out front is positive

5 0

2 years ago

Describe the sampling distribution of p(hat). Assume the size of the population is 30,000.

Naya [18.7K]

Answer:

a) $\mathbf{\mu_ \hat p = 0.6}$

b) $\mathbf{\sigma_p =0.01732}$

Step-by-step explanation:

Given that:

population mean $\mu$ = 30,000

sample size n = 800

population proportion p = 0.6

The mean of the the sampling distribution is equal to the population proportion.

$\mu_ \hat p = p$

$\mathbf{\mu_ \hat p = 0.6}$

The standard deviation of the sampling distribution can be estimated by using the formula:

$\sigma_p = \sqrt{\dfrac{p(1-p)}{n}}$

$\sigma_p = \sqrt{\dfrac{0.6(1-0.6)}{800}}$

$\sigma_p = \sqrt{\dfrac{0.6(0.4)}{800}}$

$\sigma_p = \sqrt{\dfrac{0.24}{800}}$

$\sigma_p = \sqrt{3 \times 10^{-4}}$

$\mathbf{\sigma_p =0.01732}$

7 0

3 years ago

Suppose there is a 13.9 % probability that a randomly selected person aged 40 years or older is a jogger. In addition, there is

Blababa [14]

Answer:

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

It would be unusual to randomly select a person aged 40 years or older who is male and jogs.

Step-by-step explanation:

We have these following probabilities.

A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so $P(A) = 0.13$ .

In addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male. $P(B/A)$ is the probability that the person is a male, given that he/she jogs. So $P(B/A) = 0.156$

The Bayes theorem states that:

$P(B/A) = \frac{P(A \cap B)}{P(A)}$

In which $P(A \cap B)$ is the probability that the person does both thigs, so, in this problem, the probability that a randomly selected person aged 40 years or older is male and jogs.

$P(A \cap B) = P(A).P(B/A) = 0.156*0.139 = 0.217$

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

A probability is unusual when it is smaller than 5%.

So it would be unusual to randomly select a person aged 40 years or older who is male and jogs.

4 0

3 years ago