Question

Find the solution set for this equation M^2-4=0

Answer 1

Step-by-step explanation:

Hey, there !!

Let's simply work with it,...................

Here, theequation is,

${m }^{2} - 4 = 0$

$or \: {m }^{2} = 4$

$or \: m = + - \sqrt{4}$

$or \: m = + - \sqrt{ {2}^{2} }$

cancelling square and square root we get answer is,

= (+ - 2).

It means the value of m is plus(+) minus(-) 2.

Hope it helps...