in a candy store a $5 jar of candy is labeled 50% off what is the discount what is the sale price of the jar of candy

I have a question and I cant seem figure it out. It says( Triangle ABC is a right triangle. Angle B is the right angle, side A i

pychu [463]

Answer:

you need to draw a triangle of given dimensions

Step-by-step explanation:

if B is right angle triangle then you can assume that either AB or BC is base and other one is perpendicular. So that makes AC hypotenuse

so let's assume BC is base of 6 cm. so draw a base of 6 cm line , name it BC

then draw a 90 degree angle on B keeping BC as Base . now length of perpendicular would be 4.5 cm. this perpendicular would be AB

no join A and C . length of AC should be 7.5 cm. if it's not then something is wrong in given question.

8 0

3 years ago

Solve the inequalities for x, and match each solution to its number line graph.

marysya [2.9K]

Answer:

14

Step-by-step explanation:

8 0

2 years ago

Evaluate the function. f(x) = 3x2 + 16 Find f(-1)

SIZIF [17.4K]

Answer:

$f(-1)=19$

Step-by-step explanation:

Evaluating Functions

Given a function y=f(x), evaluate the function for x=a means substituting the variable for the given value.

We have the function:

$f(x)=3x^2+16$

Find f(-1):

$f(-1)=3(-1)^2+16$

$f(-1)=3(1)+16$

$f(-1)=3+16$

$\boxed{f(-1)=19}$

4 0

3 years ago

Your swimming pool containing 60,000 gal of water has been contaminated by 6 kg of a nontoxic dye that leaves a swimmer's skin a

Paul [167]

[a] Dye is removed from the pool at a rate of

(250 gal/min) * (q/60,000 g/gal) = -q/240 g/gal

where q denotes the amount of dye in the pool at time t. Clean water is pumped back into the pool, so no dye is being re-added.

So the net rate of change of the amount of dye in the pool is given by the differential equation,

$\dfrac{\mathrm dq}{\mathrm dt}=-\dfrac{q(t)}{240}$

with the intial value, q(0) = 6000 g (or 6 kg).

[b] The ODE above is separable as

$\dfrac{\mathrm dq}q=-\dfrac{\mathrm dt}{240}$

Integrate both sides to get

$\ln|q|=-\dfrac t{240}+C$

$e^{\ln|q|}=e^{-t/240+C}$

$\implies q(t)=e^{-t/240+C}=e^{-t/240}e^C=Ce^{-t/240}$

Now plug in the initial condition:

$6000=Ce^0\implies C=6000$

so the particular solution to the IVP is

$q(t)=6000e^{-t/240}$

[c] The acceptable concentration of the dy is 0.03 g/gal, which in a pool containing 60,000 gal of water corresponds to

(0.03 g/gal) * (60,000 gal) = 1800 g = 1.8 kg

of dye. Find the time t when this occurs:

$1800=6000e^{-t/240}\implies0.3=e^{-t/240}$

$\implies\ln0.3=-\dfrac t{240}$

$\implies t=-240\ln0.3\approx288.953$

so the amount of dye in the pool is within the acceptable tolerance after about 289 min have passes, or about 4.82 hrs. So no, the filtration system is not up to the task.

8 0

3 years ago

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A bucket contains 11 2/3 gallons of water and 5/6 is full. How many gallons of water would be in a full bucket? Write a multipli

vagabundo [1.1K]

Answer:

14 gallons

Step-by-step explanation:

If 11 2/3 gallons represents 5/6 full bucket then we can equate that

x=1 full

$x=\frac {11 2/3}{5/6}=14$

Therefore, the bucket requires 14 gallons

7 0

3 years ago

Read 2 more answers