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2 years ago

I don't think the answer is C, I just clicked it because the quiz would kick me out if I didn't.

Mathematics

2 answers:

stich3 [128]2 years ago

8 0

Answer:

Step-by-step explanation:

Subtract 7x by 7, and divide 36 by 7. Or you will multiply both sides by same numbers, or divide both side with the same number.

NeX [460]2 years ago

5 0

Answer:

The correct answer is C!! ( You're correct:D )

Step-by-step explanation:

For solving the equation 7x=36, we have to divide both sides by 7;

7x/7 = 36/7

x = 36/7

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A one-tailed test is a a. hypothesis test in which rejection region is in one tail of the sampling distribution b. hypothesis te

garri49 [273]

Answer:

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

Step-by-step explanation:

One Tailed Test:

A one tailed test is a test that have hypothesis of the form

$H_0: \bar{x} = \mu\\H_A: \bar{x} < \mu\text{ or } \bar{x} > \mu$

A one-tailed test is a hypothesis test that help us to test whether the sample mean would be higher or lower than the population mean.
Rejection region is the area for which the null hypothesis is rejected.
If we perform right tailed hypothesis that is the upper tail hypothesis then the rejection region lies in the right tail after the critical value.

If we perform left tailed hypothesis that is the lower tail hypothesis then the rejection region lies in the left tail after the critical value.

Thus, for one tailed test,

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

6 0

2 years ago

Log 10(x + 3) – log 10(x-3) = 1

nadezda [96]

Answer:33/9

Step-by-step explanation:

Log10(x+3)-Log10(x-3)=1

Log10((x+3)/(x-3))=1

(x+3)/(x-3)=10^1

(x+3)/(x-3)=10

Cross multiply

x+3=10(x-3)

Open brackets

x+3=10x-30

Collect like terms

10x-x=30+3

9x=33

Divide both sides by 9

9x/9=33/9

x=33/9

4 0

3 years ago

Find the area of the shaded region.

andriy [413]

8x5 = 40
3x2 = 6

40 - 6 = 34

answer:
area of shaded = 34

3 0

3 years ago

Read 2 more answers

Find a vector of magnitude 3 in the direction of v = 10i - 24k. The vector is Oi-Oj+k (Simplify your answer. Use integers or fra

Soloha48 [4]

Given :

A vector v = 10i - 24k.

To Find :

A vector of magnitude 3 in the direction of v = 10i - 24k.

Solution :

Unit vector in the direction of vector v is :

$\^{v}=\dfrac{v}{|v|}\\\\\^{v}=\dfrac{10i-24k}{\sqrt{10^2+24^2}}\\\\\^{v}=\dfrac{10i-24k}{26}$

Now , vector of magnitude 3 in direction v is :

$r=3 \^{v}\\\\r=3\times \dfrac{ (10i-24k)}{26}\\\\r=\dfrac{3}{13} (5i-12k)$

Hence , this is the required solution .

6 0

2 years ago

What is the general form of the equation of a circle with its center at (-2,1) and passing though (-4,1) ?

julsineya [31]

Equation is :( x + 2 )² + ( y - 1 )² = r²( - 4 + 2 )² + ( 1 - 1 )² = r²4 = r², than we will plug in to a formula:( x + 2 )² + ( y - 1 )² = 4x² + 4 x + 4 + y² - 2 y +1 = 4x² + y² + 4 x - 2 y + 1 = 0
the answer is : <span>x2 + y2 + 4x − 2y + 1 = 0 </span>

4 0

3 years ago