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GuDViN [60]
3 years ago
10

The shape of the solution region for the system (picture) can be described as which of the following? Select all that apply.

Mathematics
1 answer:
borishaifa [10]3 years ago
7 0
Rectangle and parallelogram

It will have two pairs of parallel sides. 
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A cyclist rides her bike at a rate of 30 kilometers per hour. What is this rate in kilometers per minute? How many kilometers wi
SIZIF [17.4K]
5 kilometers for 10 minutes
60 minutes= 1 hour
30 kilometers divided by 60 minutes=0.5
0.5*10 minutes= 5 kilometers for 10 minutes
5 0
3 years ago
5+5 What is it........................................
Elza [17]

Answer:

I dont even want to answer this cause I know its a joke

Step-by-step explanation:

5+5=10

7 0
2 years ago
Find the vertex of this parabola.<br><br><br><br> y = -2x2 + 4x + 12
STatiana [176]
For this case we have the following equation:
 y = -2x ^ 2 + 4x + 12&#10;
 Deriving we have:
 y = -2x ^ 2 + 4x + 12&#10;&#10;y '= -4x + 4
 We match zero:
 -4x + 4 = 0&#10;
 We clear the value of x:
 4x = 4&#10;&#10;x = 4/4&#10;&#10;x = 1
 Then, we substitute the value of x in the equation of the parabola:
 y = -2 (1) ^ 2 + 4 (1) + 12&#10;&#10;y = -2 + 4 + 12&#10;&#10;y = 14
 Thus, the vertex of the parabola is the ordered pair:
 (x, y) = (1, 14)
 Answer:
 
The vertice is:
 
(x, y) = (1, 14)
3 0
3 years ago
1. L(15. 1) is the midpoint of the straight line joining point (p. - 2) to point D(-1. q) find p and q.
kkurt [141]

1. The values of p and q are: p=31 and q= 4

2. B(11, 29/5)

Further explanation:

<u>1. L(15. 1) is the midpoint of the straight line joining point (p. - 2) to point D(-1. q) find p and q.</u>

Given:

M = (15. 1)

(x1, y1) = (p, -2)

(x2, y2) = (-1, q)

The formula for mid-point is:

(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2}) = M  \\Putting\ the\ values\\(\frac{p-1}{2} , \frac{-2+q}{2}) = (15,1)\\Putting\ realtive\ values\ equal\\\frac{p-1}{2} = 15\\p-1 = 15(2)\\p-1 = 30\\p = 30+1\\p = 31\\\frac{-2+q}{2} =1\\-2+q = 2(1) \\-2+q = 2\\q = 2+2 \\q =4

Hence,

p=31

q=4

<u>2. M is the midpoint of the straight line joining point A (3. 1/5) to point B.If m has coordinates (7. 3), find the coordinates of B.​</u>

Here,

(x1,y1) = (3, 1/5)

(x2, y2) = ?

M(x,y) = (7,3)

Putting values in the formula of mid-point

(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2}) = M\\(\frac{3+x_2}{2} , \frac{1/5+y_2}{2}) = (7,3)\\\frac{3+x_2}{2} = 7\\3+x_2 = 7*2\\3+x_2 = 14\\x_2 = 14-3\\x_2 = 11\\\frac{\frac{1}{5}+y_2}{2} = 3\\{\frac{1}{5}+y_2} = 3*2\\{\frac{1}{5}+y_2} = 6\\y_2 = 6 - \frac{1}{5}\\y_2 = \frac{30-1}{5}\\y_2 = \frac{29}{5}

So, the coordinates of point B are (11, 29/5) .

Keywords: Finding mid-point, Finding coordinates through mid-point

Learn more about coordinate geometry at:

  • brainly.com/question/7437053
  • brainly.com/question/9087716

#LearnwithBrainly

6 0
3 years ago
Express the complex number in trigonometric form. 5 - 5i
bazaltina [42]

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

               Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Lets do this step by step.

This is the trigonometric form of a complex number where |z| is the modulus and 0 is the angle created on the complex plane.

z = a + bi = |z| (cos ( 0 ) + I sin (0))

The modulus of a complex number is the distance from the origin on the complex plane.

|z| = \sqrt{a^2 + b^2} where z = a + bi

Substitute the actual values of a = -5 and b = -5.

|z| = \sqrt{(-5) ^2 + (-5) ^2}

Now Find |z| .

Raise - 5 to the power of 2.

|z| = \sqrt{25 + (-5) ^2}

Raise - 5 to the power of 2.

|z| = \sqrt{25 + 25}

Add 25 and 25.

|z| = \sqrt{50}

Rewrite 50 as 5^2 . 2 .

|z| = 5\sqrt{2}

Pull terms out from under the radical.

|z| = 5\sqrt{2}

The angle of the point on the complex plane is the inverse tangent of the complex portion over the real portion.

0 = arctan (\frac{-5}{-5} )

Since inverse tangent of  \frac{-5}{-5}  produces an angle in the third quadrant, the value of the angle is \frac{5\pi }{4} .

0 = \frac{5\pi }{4}

Substitute the values of 0 = \frac{5\pi }{4} and |z| = 5\sqrt{2} .

5\sqrt{2} ( cos( \frac{5\pi}{4})  + i sin (\frac{5\pi}{4}))

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

6 0
3 years ago
Read 2 more answers
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