The sum of n terms of a geometric sequence with first term "a" and common ratio "r" is given by
You have a=21, r=3, so the sum of 10 terms is
The appropriate choice is the 2nd one:
620,004
Answer:
Red
Step-by-step explanation:
To solve this we can use substitution.
We know that y=4-x, so we can substitute "4-x" into anywhere that y appears in the first equation.
4-x=3x-8
Now we can move the variables to one side and the numbers to the other.
We can do that by adding x to both sides.
4=3x-8+x
Now, let's add 8 to both sides.
4+8=3x+x
Combine like terms.
12=4x
x=3
Now, we can plug that back into the equation to find y.
y=3(3)-8
y=8
y=1
So our answer is (3,1)
$197.08
39,500/12=3,291.66 or 3,291.67/2=1,645.835 or $1,645.84
44,230/12=3,685.83/2=1,842.915 or $1,842.92
1,842.92 - 1,645.84 = $197.08
Answer:
37
Step-by-step explanation:
f(x)=2x²−x+9
f(4)= 2(4)²-4+9
= 32-4+9
= 37
Answer:
m<5 is 105
Step-by-step explanation:
<5 and <4 are alternate interior angles meaning they are congruent to each other.