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shtirl [24]
3 years ago
7

What is the inverse of the given relation? y=3x+12

Mathematics
2 answers:
daser333 [38]3 years ago
4 0
We are asked in the problem to determine the inverse of the relation y = 3x + 12. first step is to express the equation in terms of y, that is y -12 = 3x, then exchange the places of x and y, that is x - 12 = 3y. This is the final answer
Dafna11 [192]3 years ago
3 0

Answer:

Given the relation:

y=3x+12

Step 1.

Interchange the variable x and y.

⇒x= 3y+12

Step 2.

Solve for y:

Subtract 12 from both sides we have;

x-12= 3y

Divide both sides by 3 we have;

\frac{x-12}{3} =y

or

y= \frac{x-12}{3}

therefore, the inverse function of the given relation is y = \frac{x-12}{3}

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             = \binom{n}{0}p^{0}q^{n-0} +  \binom{n}{1}p^{1}q^{n-1}+ \binom{n}{2}p^{2}q^{n-2}+ \binom{n}{3}p^{3}q^{n-3}


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             = (0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}


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