1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shtirl [24]
3 years ago
7

What is the inverse of the given relation? y=3x+12

Mathematics
2 answers:
daser333 [38]3 years ago
4 0
We are asked in the problem to determine the inverse of the relation y = 3x + 12. first step is to express the equation in terms of y, that is y -12 = 3x, then exchange the places of x and y, that is x - 12 = 3y. This is the final answer
Dafna11 [192]3 years ago
3 0

Answer:

Given the relation:

y=3x+12

Step 1.

Interchange the variable x and y.

⇒x= 3y+12

Step 2.

Solve for y:

Subtract 12 from both sides we have;

x-12= 3y

Divide both sides by 3 we have;

\frac{x-12}{3} =y

or

y= \frac{x-12}{3}

therefore, the inverse function of the given relation is y = \frac{x-12}{3}

You might be interested in
I’m confused on this one
stellarik [79]

Its a. An enlargment on a scale of 3/1.

5 0
3 years ago
Read 2 more answers
I am between 8 o clock in the morning and 3:00 in the afternoon .My number of minutes is odd i am more than half an hour away fr
Svetach [21]

Answer:

1:00 PM

Step-by-step explanation:

According to the conditions given in the question, i confirm that the time time asked here is 1:00 PM.

at 1:00 PM, its 5 minutes (odd),  clearly, more than half an hour away from the next o clock. It is closer to 5 PM than 5 AM.

8 0
4 years ago
Compute: 3 .2. -4 plzz help me
Sonja [21]
3x2x(-4)=-24
3x2-4=2
3+2-4=1
not entirely sure what the equation your asking is but i hope this helps
6 0
3 years ago
HELP WILL MARK BRAINLEIST
omeli [17]

Answer: k=3

Step-by-step explanation:

33/99 divide top and bottom by 11

33/99divided by 11/11

=3/9

7 0
4 years ago
Read 2 more answers
The mean score of 15 students was 82.0. (a) Another student joins, and the mean becomes 82.5. What is the new student's score? (
slega [8]

Answer:

a) The new student's score is 90.

b) Their scores are a pair of scores lower than 100 with a mean of 90.5.

Step-by-step explanation:

The mean is the sum of all scores divided by the number of students.

The mean score of 15 students was 82.0

This means that there are 15 students and the sum of the scores is 15*82 = 1230.

(a) Another student joins, and the mean becomes 82.5. What is the new student's score?

Now there are 16 students, the sum of the scores is 1230 + x and the mean is 82.5. So

82.5 = \frac{1230 + x}{16}

1230 + x = 16*82.5

x = 1320 - 1230

x = 90

The new student's score is 90.

(b) Suppose instead that two students join, taking the average from 82 to 83. What could their scores be, if they are restricted to be integer (i.e. whole) numbers?

Now there are 2 new students, so 17 in total. The mean score of the new students is 2x. The total score of the class is 1230 + 2x and the mean is 83. So

83 = \frac{1230 + 2x}{17}

1230 + 2x = 1411

2x = 181

x = 90.5

The mean of the two students scores is 90.5.

So their scores are a pair of scores lower than 100 with a mean of 90.5.

4 0
3 years ago
Other questions:
  • Compare the given measures<br>Important PLEASE Help Me
    6·1 answer
  • 9. What's the area of the above figure, which has sides of length 6 and 8? A. 48 B. 42 C. 14 D. 28 (its a rectangle)
    10·2 answers
  • Find the product.<br> (x + 9)(4x2 + 5x + 6)
    6·2 answers
  • If F(x) = x² + 5x and G(x) = 2x + 1, find F(5) + G(6).
    11·2 answers
  • What is the sum or product of 8×51
    10·1 answer
  • What segment is the projection of ST on QT?<br><br> UT<br> QU<br> QT
    7·2 answers
  • 6 + 8 ( x - 1) = 2 (3x + 4)
    12·1 answer
  • How big is a piece of A4 paper?​
    6·1 answer
  • Give the Domain and Range of the following function.
    13·1 answer
  • BRAINLIEST FOR BEST AND CORRECT ANSWER.
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!