Answer:
The work required to empty the tank is 1,580,887 J
Step-by-step explanation:
Work = mass of chocolate × acceleration due to gravity × height of chocolate
Volume of tank (cone) = 1/3πr^2h = 1/3 × 3.142 × 2^2 × 7 = 29.33 m^3
Mass of hot chocolate = density of hot chocolate × volume of cone = 1100 kg/m^3 × 29.33 m^3 = 32,263 kg
height of chocolate = 5 m
Work = 32,263×9.8×5 = 1,580,887 J
Answer:
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