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2 years ago

What is the primary difference between exponential and linear functions?

Mathematics

1 answer:

Yanka [14]2 years ago

4 0

Answer:

Step-by-step explanation:

We know that the growth of a linear function will always be constant. So, that eliminates B and C.

A quadratic function can be a function such as $x^2$ , or $5x^2+7x$ , etc.

An exponential function wouldn't be $x^2$ , it would be $2^x$ ! Or $3^x$ , or $(1.738283)^x$ , etc. Therefore, D is eliminated.

So, the answer is $\boxed{A}$ and we're done!

You might be interested in

Consider the following "generic rectangle" where the area of each region is given. Write equivalent

marta [7]

Answer:

sum: 3x² -4x -4
product: (x -2)(3x +2)

Step-by-step explanation:

The areas of four regions are given. We can simply add them to find the sum. To express them as a product, we need to look at common factors.

The total of the given area expressions is ...

3x² +2x -6x -4 = 3x² -4x -4 . . . . sum

<h3>Product</h3>

Extending the table to show common factors of each row and column, we have ...

$\begin{array}{c|c|c|}&3x&2\\\cline{1-3}x&3x^2&2x\\\cline{1-3}-2&-6x&-4\\\cline{1-3}\end{array}$

Since each cell of the table is the product of the corresponding common factors, we can write the area as the product ...

(x -2)(3x +2) . . . . product

8 0

1 year ago

Please help. I will give brainliest!

Andrej [43]

Answer:

Step-by-step explanation:

How to Find Outliers Using the Interquartile Range(IQR)

Step 1: Find the IQR, Q1(25th percentile) and Q3(75th percentile). ...

Step 2: Multiply the IQR you found in Step 1 by 1.5: ...

Step 3: Add the amount you found in Step 2 to Q3 from Step 1: ...

Step 3: Subtract the amount you found in Step 2 from Q1 from Step 1:

7 0

3 years ago

Ln a+3 + ln a-3 = ln 16

Lilit [14]

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)\\\\
and\qquad \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
ln(a+3)+ln(a-3)=ln(16)\implies ln[(a+3)(a-3)]=ln(16)
\\\\\\
ln[a^2-3^2]=ln(16)\impliedby \textit{removing ln() from both sides}
\\\\\\
a^2-9=16\implies a^2=16+9\implies a^2=25
\\\\\\
a=\pm\sqrt{25}\implies a=\pm 5$

7 0

3 years ago

Find the distance from the origin to the graph of 4x-y+8=0

kupik [55]

Answer:

$x=\frac{1}{4}y-2$

Step-by-step explanation:

x= 1 over 4y-2

8 0

3 years ago

Given: ⅓ (18x + 27) = 81 Prove: x = 12

sasho [114]

Answer:

Firstly, rewrite the equation:

⅓ (18 + 27) = 81

Substitute x for the given number of it's supposed equivalent.

In this case x = 12.

⅓ (18(12) + 27) = 81

Solve using PEMDAS and simplify what is in the parenthesis first. Then, multiply.

(18 x 12) + 27 = 243

Now, solving using PEMDAS, multiply the total of what you got that was originally in the parenthesis by ⅓ .

⅓ (243) = 81

When you multiple these number they are equivalent to 81.

81 = 81

Since the equation given, when substituted x for 12, is equivalent to 81, this proves that substituting x for 12 makes this equation true.

4 0

3 years ago