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Setler [38]
3 years ago
11

3c-2(c+10)=7c-5(c+2)

Mathematics
1 answer:
jeka943 years ago
6 0

Answer: C= -10

Step-by-step explanation: First step: simplify both sides of the equation

3c−2(c+10)=7c−5(c+2)

3c+(−2)(c)+(−2)(10)=7c+(−5)(c)+(−5)(2) (Distribute)

3c+−2c+−20=7c+−5c+−10

(3c+−2c)+(−20)=(7c+−5c)+(−10) (Combine Like Terms)

c + -20 = 2c - 10

c - 20 = 2c - 10

Step 2: Subtract 2c from both sides

c - 20 - 2c = 2c -10 - 2c

−c−20=−10

Step 3: Add 20 to both sides

−c−20+20=−10+20

−c=10

Step 4: Divide both sides by -1

-c/-1 = 10/-1

C=-10

   

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4 0
3 years ago
Solve the equation for an ellipse for y. Assume that y > 0. y^2/a^2 + x^2/b^2 = 1
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4 0
3 years ago
Read 2 more answers
Why is the answer undefined????? Please explain to me!! Thanks!!!!!
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1. Find two numbers with a common factor of 3 only.
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Answer:

All numbers can be written as a product of the prime numbers that conform them.

A) Find two numbers with a common factor of 3 only.

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Both numbers have the factor 3 in them, and because the other two numbers are primes, we can be sure that the 3 is the only common factor.

B) Write a pair of numbers with a common factor of 2, 3 and  6.

Here we can write:

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8 0
3 years ago
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Marizza181 [45]
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