Answer:
9 and 16
Step-by-step explanation:
let the two numbers are X and Y
X+Y=24
X^2-Y^2=144
solve simultaneously
<u>Answer:</u>
The correct answer option is B. 2 = 3x + 10x^2
<u>Step-by-step explanation:</u>
We are to determine whether which of the given equations in the answer options can be solved using the following expression:

Here,
and
.
These requirements are fulfilled by the equation 4 which is:

Rearranging it to get:

Substituting these values of
in the quadratic formula:


The dimensions of the rectangular cross section will be<u> 10 centimeters by 18 centimeters</u>
<u></u>
Step-by-step explanation:
As ,we know
<u>The rectangular cross section is parallel to the front face</u>
Which clearly states that
The dimensions of the rectangular cross section is congruent with the dimensions of the front face
Lets assume that dimensions of the front face are 10 centimeters by 18 centimeters
<u>Then ,The dimensions of the cross section will also be 10 centimeters by 18 centimeters</u>
<u></u>
<u>Hence we can say that the</u> dimensions of the rectangular cross section will be<u> 10 centimeters by 18 centimeters</u>
Answer:
a = 1, b = 1
Step-by-step explanation:
Expand the right side and compare the coefficients of like terms on both sides, that is
right side
(x - a)² + b ← expand factor using FOIL
= x² - 2ax + a² + b
Compare to left side x² - 2x + 2
Compare the coefficients of the x- term
- 2a = - 2 ( divide both sides by - 2 )
a = 1
Compare the constant terms
a² + b = 2 ( substitute a = 1 )
1² + b = 2
1 + b = 2 ( subtract 1 from both sides )
b = 1
Thus a = 1, b = 1
Answer:
1. vertical-line test
2.y=x
3.x
4.domain
Step-by-step explanation:
I just did it on edg and it’s right.