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3 years ago

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A person can pay $12.76 for a membership to the art museum and then go to the museum for just $1 per visit . What is the maximum

number of visits a member of the art museum can make for a total cost of $15.76?

1 answer:

Inessa [10]3 years ago

7 0

3 times. Hope it helped

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Find the difference <br><br> (2x+7)-6(5x-8)

sveticcg [70]

Answer:

-28x-41

Step-by-step explanation:

6*5x-6*8

30x-48

2x+7-30x-48 = 2x-30x+7-48 = -28x+7-48 = -28x+(-41)= -28x-41

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2 years ago

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At a certain electronics company, the daily output Q is related to the number of people A on the assembly line by Q=600+√(A+41).

Ber [7]

Answer:

$A=400\ people$

Step-by-step explanation:

we have

$Q=600+\sqrt{A+41}$

where

Q -----> is the daily output

A -----> is the number of people

For Q=621

Find the value of A

substitute and solve for A

$621=600+\sqrt{A+41}$

Subtract 600 both sides

$621-600=\sqrt{A+41}$

$21=\sqrt{A+41}$

squared both sides

$21^{2} ={A+41}$

$441={A+41}$

Subtract 41 both sides

$441-41=A$

Rewrite

$A=400\ people$

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3 years ago

What is 29/12 as a decimal

ivolga24 [154]

Answer:

2.4166666666 (6 forever)

Step-by-step explanation:

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3 years ago

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

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3 years ago

How do you write 210% as a decimal?

mixas84 [53]

Answer:

I believe it is 2.1 if I am wrong, very sorry.

Step-by-step explanation:

So you divide 200 by 100 so 210/100, thats when you get 2.1. So to convert that from percent to decimal all you do is is just divide by 100 and remove the % sign! Just move the decimal point 2 places to the left. If the percent value is a integer, the '.' is at the right of the right most digit.

Hope this helped you out and hope you got your answer right! Enjoy the rest of your day. :)

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3 years ago

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