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Norma-Jean [14]
3 years ago
12

15 kg 30 gm divided by 5

Mathematics
1 answer:
Naya [18.7K]3 years ago
5 0
(15 kg 30 gm) / 5= 3,00600 kiograms


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Tenemos 2000 baldosascon las que nos proponrmos embaldosar dos habitaciones.Para la 1ª gastamos 3/5 de ellas,y con la 2ª,3/4de l
Setler79 [48]

Answer:

En la primera habitación son usadas 1200 baldosas.

En la segunda habitación son usadas 600 baldosas.

Sobraron 200 baldosas.

Step-by-step explanation:

Tienes 2000 baldosas, con las que se propone embaldosar dos habitaciones.

Para la primera habitación se han gastado \frac{3}{5} de las baldosas. Esto se expresa como:

\frac{3}{5}*2000

Para multiplicar una fracción por un número entero, el número entero n se puede escribir como la fracción \frac{n}{1}. Luego se multiplica los numeradores y denominadores. En este caso:

\frac{3}{5}*2000=\frac{3}{5}*\frac{2000}{1} =\frac{3*2000}{5*1} = \frac{6000}{5}

Para reducir la fraccion, divide 40 entre 10

\frac{6000}{5} = 6000 ÷5= 1200

Entonces <u><em>en la primera habitación son usadas 1200 baldosas.</em></u> Por lo que las que quedan se calcula como:

2000 - 1200= 800 baldosas

De esta cantidad de baldosas que quedaron, \frac{3}{4} son usadas para embaldosar la segunda habitación.  Esto se expresa como:

\frac{3}{4}*800

Resolviendo de igual manera que en el caso de la primer habitación se obtiene:

\frac{3}{4}*800=\frac{3}{4}*\frac{800}{1} =\frac{3*800}{4*1} =\frac{2400}{4}= 2400 ÷ 4= 600

Entonces <u><em>en la segunda habitación son usadas 600 baldosas.</em></u> Por lo que, teniendo en cuenta que se tenían 800 baldosas que quedaron de la primera habitación, las baldosas restantes se calculan como:

800 - 600= 200 baldosas

<u><em>Sobraron 200 baldosas.</em></u>

6 0
3 years ago
Use the graph to state the solution for the system.
Svet_ta [14]

Step-by-step explanation:

I. x - y = 4 --> y = x - 4

II. x + y = 4 --> y = 4 - x

Solution is x = 4 and y = 0

3 0
3 years ago
Can someone help me please?
taurus [48]

Answer:

the only answer that makes sense would be the length

4 0
3 years ago
1/6 to the third power
GenaCL600 [577]
I believe the answer is 1/216
3 0
4 years ago
Read 2 more answers
Mrs.smells math class has 20 questions worth 100 points. if the multiple choice are worth 3 points and the short answer is worth
andreyandreev [35.5K]
Let, Number of multiple choice = x
Number of short answer question = y

Now, x + y = 20
& 3x + 11y = 100

Multiply 1st equation by 3, and subtract from eq,2, 
3x + 3y = 60
After subtraction, 
8y = 40
y = 40/8
y = 5

Now, substitute in eq (1), 
x + 5 = 20
x = 15

In short, There are 15 Multiple choice & 5 short answer questions

Hope this helps!
4 0
3 years ago
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