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Sergeu [11.5K]
3 years ago
9

What are the next three terms in these 2 sequences? 1. 3, 8, 23, 68 2. 2, 6, 18

Mathematics
1 answer:
Karolina [17]3 years ago
3 0

1:
3*3=8 ;
8*3=23
23*3=68
68*3=204
1.3,8,23,68,204 ... 

2.
2*3=6
6*3=18
18*3=54
2, 6,18,54


multiply all on 3)

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The newly elected president needs to decide the remaining 5 spots available in the cabinet he/she is appointing. If there are 15
skad [1K]

Answer: There are 360360 ways to appoint the members of the cabinet.

Step-by-step explanation:

Since we have given that

Number of eligible candidates = 15

Number of spots available = 5

We need to find the number of different ways the members can be appointed where rank matters

For this we will use "Permutations":

So, the required number of different ways in choosing the members for appointment is given by

^{15}P_5=360360

Hence, there are 360360 ways to appoint the members of the cabinet.

7 0
3 years ago
In a study of the accuracy of fast food drive-through orders, McDonald’s had 33 orders that were not accurate among 362 orders o
melomori [17]

Answer:

A. We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B. Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

C. z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558  

D. z_{\alpha/2}=-1.96  z_{1-\alpha/2}=1.96

E. Fail to the reject the null hypothesis

F. So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.  

Step-by-step explanation:

Data given and notation

n=362 represent the random sample taken

X=33 represent the number of orders not accurate

\hat p=\frac{33}{363}=0.0912 estimated proportion of orders not accurate

p_o=0.10 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

A: Write the claim as a mathematical statement involving the population proportion p

We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B: State the null (H0) and alternative (H1) hypotheses

Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

C: Find the test statistic

Since we have all the info required we can replace in formula (1) like this:  

z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558  

D: Find the critical value(s)

Since is a bilateral test we have two critical values. We need to look on the normal standard distribution a quantile that accumulates 0.025 of the area on each tail. And for this case we have:

z_{\alpha/2}=-1.96  z_{1-\alpha/2}=1.96

P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

E: Would you Reject or Fail to Reject the null (H0) hypothesis.

Fail to the reject the null hypothesis

F: Write the conclusion of the test.

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.  

6 0
3 years ago
Help me please thankyou
Aloiza [94]

Ask your parents about it if they didn't help you can copy mine,

Well I asked my parents about they told me that around their age there weren't lots of facilities they even rarely saw transportation facilities like cars and bikes there were no proper internet facilities e.t.c

When I said them what were the changes in the last 25 years they said there were drastic changes including social, economic, science, transportation, health e.t.c and many more

4 0
2 years ago
What makes this a binomial distribution and what is the probability?
kati45 [8]

Answer:

Probability at least one car will get punctured: 0.39347

Step-by-step explanation:

B(10,000 , 0.00005)

P(X ≥ 1) = 1 - P(X = 0)

            = 1 - (1 - 0.00005)^10,000

            = 1 - (0.99995)^10,000

            = 1 - 0.60652...

            = 0.39347 (probability that at least one car will get punctured)

As you can tell P(X ≥ 1) as we have to solve for the probability that at least one car will get punctured. That is of course 1 - [ P(X = 0) ].

3 0
3 years ago
Read 2 more answers
A freight elevator is being loaded with identical 76-pound boxes. The elevator can carry no more than 2000 pounds. How many boxe
pishuonlain [190]
Take 2000 divide 76 =26.3 so the elevator can carry 26 boxes
4 0
4 years ago
Read 2 more answers
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