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3 years ago

X + 12/x + 2 = x/x + 8 A) X = -4 B) X = 8 C) X = 6 D) X = -6

Mathematics

1 answer:

xxMikexx [17]3 years ago

4 0

I got x = 96/18 i dont think the answer is there

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How do I solve this plz show steps

lord [1]

Copy it just like this I'm in geometry. Glad to help

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4 years ago

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HELP, I can't figure out the first question

Margarita [4]

The answer is linearly

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3 years ago

A random sample of 12 students used Method A, and their increase in points averaged 46.31, with a sample standard deviation of 6

Kitty [74]

Answer:

The null hypothesis is $H_o : \mu_A - \mu_B = 0$

The alternative hypothesis is $H_a : \mu_A - \mu_B > 3$

Step-by-step explanation:

From the question we are told that

The mean of method A is $\mu_A = 46.31$

The standard deviation of method A is $\sigma = 6.44$

The mean of method B is $\mu_B = 42.79$

The standard deviation of method B is $\sigma_B = 7.52$

An appropriate set of null and alternative hypothesis to determine whether Method A increases students points by more than 3 points is

The null hypothesis is $H_o : \mu_A - \mu_B = 0$

The alternative hypothesis is $H_a : \mu_A - \mu_B > 3$

6 0

3 years ago

Simplify (4xy^-2)/(12x^(-1/3)y^-5) and Show work ...?

oee [108]

The answer is $\frac{x^{4/3}y^{3}}{3}$ .

The fraction is: $\frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }$
Let's rewrite it: $\frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }=\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }$

Since $\frac{x^{a} }{x^{b}} =x^{a-b}$ ,
then:
*** $\frac{x}{ x^{-1/3} }= x^{1-(-1/3)} = x^{3/3+1/3} = x^{4/3}$
*** $\frac{y^{-2} }{ y^{-5} }= y^{-2-(-5)} = y^{-2+5} = y^{3}$
______
$\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }= \frac{1*4}{3*4}* x^{4/3}*y^{3}= \frac{1}{3} * x^{4/3}*y^{3}= \frac{x^{4/3}y^{3}}{3}$

8 0

3 years ago

galina1969 [7]

Answer:

Herbivore

Step-by-step explanation:

The mouse isnt a producer because he cannot make his own food

The mouse isnt a carnivore because he isnt eating meat

The mouse isnt a decomposer because he isnt breaking down dead or decaying organisms

Herbivores are animals that eat vegetables or greens/plants but not meat.

6 0

4 years ago

Read 2 more answers