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3 years ago

Which in is it.........

Mathematics

1 answer:

ANTONII [103]3 years ago

8 0

I haven't done these problems in a really long time, so there's a chance that my answer might be wrong. I hypothesize that the correct answer is C.

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Half of a dome is called what?

Vesna [10]

Answer:

See I don't know the Answer but I Need points to ask question so Sorry

Step-by-step explanation:

3 0

3 years ago

Write the rational number -1, in the form , where a and b are<br> integers.

iogann1982 [59]

Answer:

2nd option

Step-by-step explanation:

- 5 = $\frac{-5}{1}$ ← in the form $\frac{a}{b}$

3 0

3 years ago

the height of a plant in centimeters is modeled as a function of time, in days. consider this graph of the function enter the av

MrRa [10]

The average rate of change for the height of the plant measured in centimeters per day between day 0 and day 20 is 1.32 cm per day.

<h3>What is average height?</h3>

The average height is the ratio of change in height of the plant and the time taken taken for that change.

Given is the height of a plant in centimeters is modeled as a function of time, in days.

For day 0, the height is 18cm and the height for day 20 is 42 cm, then the average height change is

height per day = 42 - 18/ 20 -0

height per day = 1.2 cm/day

Thus, the average height of plant is 1.2 cm/day.

Learn more about average height.

brainly.com/question/16490045

#SPJ1

6 0

2 years ago

Polygon A is a square. Polygon B has four more sides than polygon A. What type of polygon is B?

Assoli18 [71]

Answer:

OCTAGON for question 1

Step-by-step explanation:

that's it an eight sided polygon is an octagon

8 0

3 years ago

Read 2 more answers

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago