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spayn [35]
3 years ago
13

Arithmetic of Functions problem.

Mathematics
2 answers:
FromTheMoon [43]3 years ago
5 0

Answer:

(f o g)(4) = 45  

Step-by-step explanation:

We have given two functions and we have to find their composition.

f(x) = 4x+1   , g(x) = x²-5  

Firstly, we have to find (f o g)(x)

Then, we have to find (f o g)(x).

(f o g)(x) = f(g(x))

Putting the given values of functions in above formula , we have

(f o g)(x) = f(x²-5)

(f o g)(x) = 4(x²-5)+1

simplifying

(f o g)(x) = 4x²-20+1

adding like terms, we have

(f o g)(x) = 4x²-19

Putting x = 4   to above equation , we have

(f o g)(4) = 4(4)²-19

(f o g)(4) = 4(16)-19

(f o g)(4) = 64-19

(f o g)(4) = 45  which is the answer.

lidiya [134]3 years ago
4 0

Answer:

(f o g)(4) = 45

Step-by-step explanation:

f(x)=4x+1

g(x)=x²-5

(f o g)(4)=?

(f o g)(4) = f(g(4))


Calculating g(4):

x=4→g(4)=4²-5

g(4)=16-5

g(4)=11


Replacing g(4)=11

(f o g)(4) = f(g(4))

(f o g)(4) = f(11)


Calculating f(11)

x=11→f(11)=4(11)+1

f(11)=44+1

f(11)=45


Replacing f(11)=45:

(f o g)(4) = f(11)

(f o g)(4) = 45

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<h2>Step-by-step explanation:</h2>

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One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

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