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Dahasolnce [82]
2 years ago
11

The distances of a port from 20 differ- ent locations form an AP. If the farthest distance is 300 km, and the nearest distance i

s 30 km, what is the distance between any two successive locations? ?​
Mathematics
1 answer:
Mkey [24]2 years ago
5 0

Answer:

Required difference = 270/19 km

Step-by-step explanation:

If we consider the AP of distances to be

a, a + r, a + 2r, ..., a + 19r,

where a is the distance of the nearest location from the port and r is the difference between any two successive location.

Given that,

a + 19r = 300 .....(1)

a = 30 ..... (2)

Using (2), from (1), we get

30 + 19r = 300

or, 19r = 300 - 30

or, 19r = 270

or, r = 270/19

Therefore the distance between any two successive location is 270/19 km.

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Hello from MrBillDoesMath!


Answer:

Interest paid = $ 1,713,568.73

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From the "compound interest formula:

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