Solve 2x-8=-2-8. How do I do this

Mathematics

2 answers:

lisov135 [29]3 years ago

7 0

Its Easy You Just Need To Use The Algebraic Method

faust18 [17]3 years ago

5 0

Is that negative 2 minus 8? if so put that into the calculator and add 8 to both sides and divide by 2 after that. simple algebra

You might be interested in

Tysrusuhxguyuxytwsys

LUCKY_DIMON [66]

Thx tahayahahataghaahtsyaha

7 0

3 years ago

Which equation can be used to solve for x in the following diagram?

jonny [76]

Step-by-step explanation:

B because the straight angle must be 180°

5 0

3 years ago

Read 2 more answers

Can anyone help me solve a trigonomic identity problem and also help me how to do it step by step?

dusya [7]

$\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad csc(\theta)=\cfrac{1}{sin(\theta)}
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\\\\
-------------------------------\\\\$

$\bf \cfrac{cos(\theta )cot(\theta )}{1-sin(\theta )}-1=csc(\theta )\\\\
-------------------------------\\\\
\cfrac{cos(\theta )\cdot \frac{cos(\theta )}{sin(\theta )}}{1-sin(\theta )}-1\implies \cfrac{\frac{cos^2(\theta )}{sin(\theta )}}{\frac{1-sin(\theta )}{1}}-1\implies 
\cfrac{cos^2(\theta )}{sin(\theta )}\cdot \cfrac{1}{1-sin(\theta )}-1
\\\\\\
\cfrac{cos^2(\theta )}{sin(\theta )[1-sin(\theta )]}-1\implies 
\cfrac{cos^2(\theta )-1[sin(\theta )[1-sin(\theta )]]}{sin(\theta )[1-sin(\theta )]}$

$\bf \cfrac{cos^2(\theta )-1[sin(\theta )-sin^2(\theta )]}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{cos^2(\theta )-sin(\theta )+sin^2(\theta )}{sin(\theta )[1-sin(\theta )]}
\\\\\\
\cfrac{cos^2(\theta )+sin^2(\theta )-sin(\theta )}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{\underline{1-sin(\theta )}}{sin(\theta )\underline{[1-sin(\theta )]}}
\\\\\\
\cfrac{1}{sin(\theta )}\implies csc(\theta )$

7 0

3 years ago

How many times does 48 go into 80

anastassius [24]

1.666666666666667 to be exact, but rounded it is 1.66

3 0

3 years ago

Read 2 more answers

Please help it will be greatly appreciated :)

Sergio039 [100]

It it 270 degrees for the shaded part of it

7 0

3 years ago