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vivado [14]
3 years ago
9

While on vacation, the Jacobson family drove 312.8 miles the first day, 177.2 miles the second day, and 209 miles the third day.

About how many miles did they travel in all?
Mathematics
1 answer:
quester [9]3 years ago
8 0
Literally just add it all up.
312.8+177.2+209=699 miles
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Evaluate the expression x - 7. If x= 12.<br> 19<br> 6<br> 17<br> 5
ratelena [41]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{5}}}}}

Step-by-step explanation:

Given , value of x = 12

To find : Value of the given expression

Given expression = \sf{x - 7 }

plug the value of x

\dashrightarrow{ \sf{ 12 - 7}}

Subtract 7 from 12

\dashrightarrow{ \sf{5}}

Hope I helped!

Best regards! :D

8 0
4 years ago
Pls help me .question no 14
Alex_Xolod [135]

Question 14, Part (i)

Focus on quadrilateral ABCD. The interior angles add to 360 (this is true for any quadrilateral), so,

A+B+C+D = 360

A+90+C+90 = 360

A+C+180 = 360

A+C = 360-180

A+C = 180

Since angles A and C add to 180, this shows they are supplementary. This is the same as saying angles 2 and 3 are supplementary.

==================================================

Question 14, Part (ii)

Let

x = measure of angle 1

y = measure of angle 2

z = measure of angle 3

Back in part (i) above, we showed that y + z = 180

Note that angles 1 and 2 are adjacent to form a straight line, so we can say

x+y = 180

-------

We have the two equations x+y = 180 and y+z = 180 to form this system of equations

\begin{cases}x+y = 180\\y+z = 180\end{cases}

Which is really the same as this system

\begin{cases}x+y+0 = 180\\0+y+z = 180\end{cases}

The 0s help align the y terms up. Subtracting straight down leads to the equation x-z = 0 and we can solve to get x = z. Therefore showing that angle 1 and angle 3 are congruent. We could also use the substitution rule to end up with x = z as well.

4 0
4 years ago
What is the equation of the line that passes through the point (-2,5) and has a<br> slope of -4?
adoni [48]

Answer:

\boxed {\boxed {\sf y= -4x -3}}

Step-by-step explanation:

We are asked to find the equation of a line given a point and the slope. We will use the point-slope formula.

y-y_1= m(x-x_1)

In this formula, m is the slope and (x₁, y₁) is the point the line passes through. The slope of this line is -4 and the line passes through (-2,5).

  • m= -4
  • x₁= -2
  • y₁ = 5

Substitute the values into the formula.

y-5 = -4 (x--2)

y-5 = -4 (x+2)

We are finding the equation of the line, so we should find the slope-intercept form or y=mx+b ( where m is the slope and b is the y-intercept).We must isolate the variable y on one side of the equation.

First, distribute the -4 on the right side of the equation. Multiply each term inside the parentheses by -4.

y-5=( -4 *x ) + (-4* 2 )

y-5 =(-4x)+ (-8)\\y-5= -4x -8

5 is being subtracted from y. The inverse operation of subtraction is addition, so we will add 5 to both sides of the equation.

y-5 =-4x -8 + 5

y= -4x -3

The equation of the line is y= -4x -3. The slope of the line is -4 and the y-intercept is -3.

6 0
3 years ago
Observe the graph below.<br> The graph shows a<br> function that is asymptotic to
JulijaS [17]
We have to see the graph to what the answer is. Sorry I wish I could help!
4 0
3 years ago
How do you solve 8-(4x+7)=5x+30-2?
Cerrena [4.2K]
8-4x-7=5x+30-2
combine like terms
1-4x=5x+28
-27=9x
divide both sides by nine
-3=x
6 0
3 years ago
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